這是我所使用的@JsonDeserialize定製解串器從來沒有所謂
@Transient
@JsonDeserialize(using = SharedUserDeserializer.class)
private Set<UserVehicleMappingVO> sharedVehicle;
public Set<UserVehicleMappingVO> getSharedVehicle() {
return sharedVehicle;
}
public void setSharedVehicle(Set<UserVehicleMappingVO> sharedVehicle) {
this.sharedVehicle = sharedVehicle;
}
而定製的解串器代碼的屬性是
public class SharedUserDeserializer extends JsonDeserializer<Set<UserVehicleMappingVO>> {
@Override
public Set<UserVehicleMappingVO> deserialize(JsonParser paramJsonParser,
DeserializationContext paramDeserializationContext)
throws IOException, JsonProcessingException {
try {
Set<UserVehicleMappingVO> list = new ObjectMapper().readValue(paramJsonParser.toString(),
new TypeReference<Set<UserVehicleMappingVO>>() {});
return list;
} catch (IOException e) {
e.printStackTrace();
}
return new HashSet<>();
}
}
但解串器永遠不會被調用。請幫助
每次我得到這個異常,而不是....
ERROR :::9,[email protected] - Exception in
method===org.springframework.validation.BeanPropertyBindingResult: 1 errors
Field error in object 'trackee' on field 'sharedVehicle': rejected value
[[{"userId":"5d48b74f-7da2-11e7-87bf-
1383429d1d89","expireTime":1504190100000}]]; codes
[typeMismatch.trackee.sharedVehicle,typeMismatch.sharedVehicle,
typeMismatch.java.util.Set,typeMismatch]; arguments
[org.springframework.context.support.DefaultMessageSourceResolvable: codes
[trackee.sharedVehicle,sharedVehicle]; arguments []; default message
[sharedVehicle]]; default message [Failed to convert property value of type
[java.lang.String] to required type [java.util.Set] for property
'sharedVehicle'; nested exception is java.lang.IllegalStateException: Cannot
convert value of type [java.lang.String] to required type
[com.azuga.user.manager.UserVehicleMappingVO] for property
'sharedVehicle[0]':
請幫助........
爲什麼@Transient?你想在序列化過程中忽略該字段? – Barath
@Barath:瞬態是爲了讓hibernate忽略這個字段,同時堅持表...這與序列化無關。 – Sabya
感謝您的教育。因爲我無法找到任何暫時的import語句,我認爲它必須使用java序列化來完成某些操作。 – Barath