顯示多個結果數組

Question

到目前爲止，我已經得到了我的應用程序的工作，但我現在面臨一個問題。僅供參考，我的應用程序是關於獲取用戶輸入（用戶輸入一些句子，應用程序將查找含糊不清的單詞並顯示其含義）。

這是我的代碼：

final String[] words = {"cowboy", "animal" , "monster", "duck"}; 
final String[] meanings = { "meaning1", "meaning2", "meaning3", "meaning4" }; 

private void initControls() { 
// TODO Auto-generated method stub 
text = (EditText) findViewById (R.id.editText1); 

view = (TextView) findViewById (R.id.textView1); 

clear = (Button) findViewById (R.id.button2); 

clear.setOnClickListener(new View.OnClickListener() { 

    @Override 
    public void onClick(View v) { 
     // TODO Auto-generated method stub 
     text.setText(""); 
     view.setText(""); 
    } 
}); 

ok = (Button) findViewById (R.id.button1); 
ok.setOnClickListener(new View.OnClickListener() { 

    @Override 
    public void onClick(View v) { 
     // TODO Auto-generated method stub 
     findAmbiguousWord(); 
    } 
}); 
} 

private void findAmbiguousWord(){ 
String string = text.getText().toString(); 

int index = 0; 

for (int i = 0; i < words.length; i++) { 
    if (string.toLowerCase().contains(words[i].toLowerCase())) { 
     check = true; 
     index = i; 
    } 
} 

view.setText(check ? meanings[index] : "No ambiguous word/s found."); 
} 

但每當I型一句話：

My friend is a cowboy. He is also fond of duck. 

它僅顯示第一個字即COWBOY。我如何顯示其他字詞？幫助是非常需要和讚賞的。提前致謝！

Answer 1

你可以在集合中添加的結果，例如一個Set或List：

private void findAmbiguousWord(){ 
String string = text.getText().toString(); 
// create a set to store the results 
Set<String> result = new HashSet<String>(); 
for (int i = 0; i < words.length; i++) { 
    if (string.toLowerCase().contains(words[i].toLowerCase())) { 
     // ambiguous word, we need its meaning! 
     result.add(meanings[i]); 
    } 
} 

// display the results if there are some 
view.setText(result.isEmpty() ? "No ambiguous word/s found." : result.toString()); 
} 

Answer 2

使用索引列表或在循環中構建您的輸出字符串，而不是僅存儲一個索引。

Answer 3

StringBuilder ambiguousWords = new StringBuilder(); 
for (int i = 0; i < words.length; i++) { 
    if (string.toLowerCase().contains(words[i].toLowerCase())) { 
     check = true; 
     ambiguousWords.append(meanings[i]); 
    } 
} 

view.setText(check ? "No ambiguous word/s found." : ambiguousWords.toString());