Spring.Net編程與XML配置

Question

如果我使用XML定義對象並調用var xmlApplicationContext = new XmlApplicationContext()，那麼該作業將被調度並觸發。我想要完成的是通過代碼來完成此操作，因爲屬性是動態的，下面的方法片段編譯並運行，但作業未安排。這可能嗎？

// SpringJob.xml

<objects xmlns="http://www.springframework.net" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> 
     <object name="emailNotification" type="Spring.Scheduling.Quartz.JobDetailObject, Spring.Scheduling.Quartz"> 
      <property name="JobType" value="Project.Agent.Jobs.EmailNotification, Project.Agent" /> 
     </object> 
     <object id="simpleTrigger" type="Spring.Scheduling.Quartz.SimpleTriggerObject, Spring.Scheduling.Quartz"> 
      <property name="jobDetail" ref="emailNotification" /> 
      <property name="startDelay" value="1s" /> 
      <property name="repeatInterval" value="1s" /> 
      <property name="repeatCount" value="0" /> 
     </object> 
     <object type="Spring.Scheduling.Quartz.SchedulerFactoryObject, Spring.Scheduling.Quartz"> 
      <property name="triggers"> 
       <list> 
        <ref object="simpleTrigger" /> 
       </list> 
      </property> 
     </object> 
</objects> 

//方法

var jobDetailObject = new JobDetailObject 
               { 
                JobType = new EmailNotification().GetType() 
               }; 

    var simpleTrigger = new SimpleTriggerObject 
          { 
           JobDetail = jobDetailObject, 
           StartDelay = new TimeSpan(0, 0, 0, 1), 
           RepeatInterval = new TimeSpan(0, 0, 0, 1), 
           RepeatCount = 0 
          }; 

    var scheduleTrigger = new SchedulerFactoryObject(); 
    var triggers = new Trigger[1]; 
    triggers[0] = simpleTrigger; 
    scheduleTrigger.Triggers = triggers; 
    scheduleTrigger.Start(); 

Answer 1

決定放棄Quartz.Net的Spring.Net框架實現，而不是我直接用Quartz.Net。