Phalcon PHP致命錯誤：未知的異常與消息「未知的表達式」

Question

我試圖按照REST應用程序教程provided by Phalcon，但我試圖插入數據時仍遇到問題。我的問題是，我不知道這個錯誤應該是什麼意思。我相信這在Phalcon中是一個錯誤，但我對C的知識是不存在的。讓我知道我是否應該提供更多的上下文。

下面是在PHP的錯誤日誌顯示了錯誤：

PHP Fatal error: Uncaught exception 'Phalcon\\Mvc\\Model\\Exception' with message 'Unknown expression' in /home/acarbonaro/testApplication/index.php:84\n 
Stack trace:\n 
0 [internal function]: Phalcon\\Mvc\\Model\\Query->_getExpression(274, false)\n 
1 [internal function]: Phalcon\\Mvc\\Model\\Query->_prepareInsert()\n 
2 [internal function]: Phalcon\\Mvc\\Model\\Query->parse()\n 
3 [internal function]: Phalcon\\Mvc\\Model\\Query->execute(Array, NULL)\n 
4 /home/acarbonaro/testApplication/index.php(84): Phalcon\\Mvc\\Model\\Manager->executeQuery('INSERT INTO Pro...', Array)\n 
5 [internal function]: {closure}()\n 
6 /home/acarbonaro/testApplication/index.php(115): Phalcon\\Mvc\\Micro->handle()\n 
7 {main}\n 
    thrown in /home/acarbonaro/testApplication/index.php on line 84 

這是一個有行號的POST路線供參考的代碼。

71: $app->post('/api/products', function() use ($app) { 
72:  if ($app->request->isPost() == true) { 
73:   if ($app->request->isAjax() == true) { 
74:    $product = $app->request->getJsonRawBody(); 
75:    $partNumber = $product->partNumber; 
76:   } 
77:   $partNumber = $app->request->getPost('partNumber'); 
78:  } 
79: 
80:  $phql = "INSERT INTO Products (partNumber) VALUES (:partNumber:)"; 
81:  $params = array(
82:   'partNumber' => $partNumber 
83: ); 
84:  $status = $app->modelsManager->executeQuery($phql, $params); 
85: 
86:  // Prep the response 
87:  if ($status->success() == true) { 
88:   $response->setStatusCode(201, "Created"); 
89: 
90:   $product->id = $status->getModel()->id; 
91: 
92:   $response->setJsonContent(array('status' => 'OK', 'data' => $product)); 
93:  } else { 
94:   $response->setStatusCode(409, "Conflict"); 
95: 
96:   // Send errors to the client 
97:   $errors = array(); 
98:   foreach($status->getMessages() as $message) { 
99:    $errors[] = $message->getMessage(); 
100:   } 
101: 
102:   $response->setJsonContent(array('status' => 'ERROR', 'messages' => $errors)); 
103:  } 
104: 
105:  return $response; 
106: }); 

Answer 1

80:  $phql = "INSERT INTO Products (partNumber) VALUES (:partNumber)"; 
81:  $params = array(
82:   ':partNumber' => $partNumber 
83: ); 
84:  $status = $app->modelsManager->executeQuery($phql, $params); 

我有這個爾康你講的沒有經驗，但是從堆棧跟蹤它似乎使用PDO。

80行：刪除了最後一個冒號有... VALUES（：部分號碼）「;

82行：加冒號數組鍵的開始，所以你必須 '：PARTNUMBER'=>

這將隨後是一個有效的PDO準備（）語句。您的里程可能會有所不同，但是這會是一個很好的起點。