我有一個名爲'questions'的數組,我有一個與它關聯的對象變量,它也是一個名爲'choices'的數組。數組對象
var questions = [
{
question: "What type of business do you run?",
choices: ['Business to Business - Provide products and/or services to other
businesses', 'Business to Business to Consumer - Provide products
and/or services to other businesses for consumers',
'Business to Consumer - Provide products and/or services to
consumers'],
choiceValues: [1, 2, 3],
}
我想在for循環中使用「選擇」的長度,如下所示。這句法正確嗎?我似乎無法增加「點數」變量。
function displayScore()
{
var score = $('<p>',{id: 'question'});
var points = 0;
for (var i = 0; i < selections.length; i++)
{
for (var j = 0; j < questions[i].choices.length; j++)
{
if (selections[i] === questions[i].choices[j])
{
points = points + questions[i].choiceValues[j];
}
}
}
score.append('You got ' + points + ' points!');
return score;
}
'選擇'的一個例子是:[0,4,0,1,0,1,0,1]。
你已經驗證了什麼'的問題[I] .choices [j]'是?它與您所期望的相符嗎?另外,什麼是「選擇」? – Carcigenicate
@Carcigenicate'selections'是一個包含用戶對問題的答案的數組。我使用inner for循環來檢查他們的答案匹配列表中哪個答案。根據匹配的答案,分配一定數量的點,由'choiceValues'定義。 –
提供'選擇'的示例 – luisenrike