我有這個準備好的聲明,我不知道如何來遍歷,它看起來像這樣:PHP預處理語句foreach循環
<?php
//if ($_SERVER['REQUEST_METHOD'] === 'POST') {
require('../includes/db_connect.php');
$i = 40;
foreach ($_POST['item'] as $value) {
/* Register a prepared statement */
if ($stmt = $mysqli->prepare('
UPDATE house_room1 SET z = ? WHERE object_id = ?
')) {
/* Bind parametres */
$stmt->bind_param('ii', $object_id, $i);
/* Insert the parameter values */
$object_id = 1;
$i = $i;
/* Execute the query */
$stmt->execute();
/* Close statement */
$stmt->close();
} else {
/* Something went wrong */
echo 'Something went terribly wrong' . $mysqli->error;
}
$i++;
}
//}
?>
我希望它在z添加一個新的價值,但現在它甚至不知道$i
是什麼。呃,任何想法,建議或建議?提前致謝。
'$ I = $ I;'你在哪裏最初設置'$ i'的價值? –
$ _POST ['item']在哪裏起作用?這是否成爲object_id? – larsAnders