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我不能夠解決這個錯誤：XmlPullParser異常
org.xmlpull.v1.XmlPullParserException: expected: START_TAG { http://www.w3.org/2001/12/soap-envelope }Envelope (position:START_TAG @1:6 in [email protected])
我有一個Android應用程序，其訪問.NET Web服務。它傳遞一個int並接收一個int作爲響應。我正在使用ksoap2。 我也向清單文件添加了權限，而且我還包含了所有的jar文件。然而，我卡住了，我無法查看我發送的SOAP請求。
我的代碼是：提前
public class FirstAppUI extends Activity{
private static final String NAMESPACE = "http://tempuri.org/";
private static final String URL =
"http://nautilussoft.biz.whbus12.onlyfordemo.com/staging/litigation/demowebservice.asmx";
private static final String SOAP_ACTION ="http://tempuri.org/GetNumber";
private static final String METHOD_NAME = "GetNumber";
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
TextView tv= (TextView)findViewById(R.id.TextView01);
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("maxbelow", "123");
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
envelope.dotNet= true;
envelope.setOutputSoapObject(request);
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try {
//Toast.makeText(getBaseContext(), "received object", Toast.LENGTH_SHORT).show();
androidHttpTransport.call(SOAP_ACTION, envelope);
Object resultsRequestSOAP = (SoapObject)envelope.getResponse();
//SoapObject resultsRequestSOAP = (SoapObject) envelope.bodyIn;
//Toast.makeText(getBaseContext(), "received object", Toast.LENGTH_SHORT).show();
tv.setText("Received :" + resultsRequestSOAP.toString());
} catch (MalformedURLException e) {
e.printStackTrace();
Log.e("APP", "MalformedURLException while sending\n" + e.getMessage());
tv.setText("Malformedexception"+e);
}
catch(Exception e1)
{
e1.printStackTrace();
tv.setText("exception"+e1);
}
}
}
感謝。