2010-01-02 30 views

回答

0

爲了得到一個JSON字符串到PHP對象:

$obj = json_decode($some_json); 
echo $obj->field1; // where field1 is a known field 

得到一個JSON字符串的關聯數組:

$arr = json_decode($some_json, true); 
echo $arr['field1']; 
1

據我瞭解,您需要json_decode()函數。您可以陣列JSON格式的編碼很容易地轉換到PHP陣列

+1

也就是說,通過ajax或通過表單提交將其提交給php腳本後。 –