2017-08-29 69 views
1

錯誤進口角JS

<!DOCTYPE html> 
 
<html> 
 
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script> 
 
<body> 
 

 
    <div ng-app="myApp" ng-controller="myCntrl"> 
 
    First Name : <input type="text" ng-model="firstName"> <br> 
 
    Last Name : <input type="text" ng-model="lastName"> <br> 
 
    <br> 
 
    Full Name: {{firstName + " " + lastName}} 
 
    </div> 
 

 
    <script> 
 
    var person={ 
 
    firstName = "john" , 
 
    lastName = "Doe" 
 
    }; 
 

 
    var app = angular.module('myApp', []); 
 
    app.controller('myCntrl', function($scope){ 
 
    $scope.firstName = person.firstName; 
 
    $scope.lastName = person.lastName 
 
    }); 
 
    </script> 
 
</body> 
 
</html>

,但我得到這個運行

angular.js:38 Uncaught Error: [$injector:modulerr] http://errors.angularjs.org/1.6.4/ $injector/modulerr?p0=myApp&p1=Error%3A%20%5B%24injector%3Anomod%5D%20http%3A%2F%2Ferrors.angularjs.org%2F1.6.4%2F%24injector%2Fnomod%3Fp0%3DmyApp%0A%20%20%20%20at%20https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A6%3A425%0A%20%20%20%20at%20https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A26%3A270%0A%20%20%20%20at%20b%20(https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A25%3A299)%0A%20%20%20%20at%20https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A26%3A44%0A%20%20%20%20at%20https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A42%3A117%0A%20%20%20%20at%20q%20(https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A7%3A495)%0A%20%20%20%20at%20g%20(https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A41%3A476)%0A%20%20%20%20at%20eb%20(https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A46%3A44)%0A%20%20%20%20at%20c%20(https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A21%3A373)%0A%20%20%20%20at%20Sc%20(https%3A%2F%2Fajax.googleapis.com%2Fajax%2Flibs%2Fangularjs%2F1.6.4%2Fangular.min.js%3A22%3A179) at angular.js:38 at angular.js:4920 at q (angular.js:403) at g (angular.js:4880) at eb (angular.js:4802) at c (angular.js:1914) at Sc (angular.js:1935) at ue (angular.js:1820) at angular.js:33367 at HTMLDocument.b (angular.js:3431)

任何幫助的時候?

回答

1

您必須在角度範圍內使用正確的語法正確聲明person對象。所以移動控制器內的對象。

var app = angular.module('myApp', []); 
 
    app.controller('myCntrl', function($scope) { 
 
     var person = { 
 
      firstName: "john", 
 
      lastName: "Doe" 
 
     }; 
 
     $scope.firstName = person.firstName; 
 
     $scope.lastName = person.lastName 
 
    });
<!DOCTYPE html> 
 
<html> 
 
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.4.8/angular.min.js"></script> 
 

 
<body> 
 
    <div ng-app="myApp" ng-controller="myCntrl"> First Name : 
 
     <input type="text" ng-model="firstName"> 
 
     <br> Last Name : 
 
     <input type="text" ng-model="lastName"> 
 
     <br> 
 
     <br> Full Name: {{firstName + " " + lastName}} </div> 
 
</body> 
 

 
</html>

+0

是什麼問題? –

+0

檢查更新的答案。您的對象聲明不正確,最好在angularjs應用程序的作用域中將person用作對象,而不是將其聲明爲全局對象。 – Vivz

+0

即使您在全局聲明變量,它也會工作,但不建議 – Vivz