2016-11-22 45 views

回答

0

請嘗試以下方法。它列出了所有問題已經回答的所有PSPID。

SELECT DISTINCT qq.PSPID 
    FROM PSP_QUESTION_MASTER AS qq 
WHERE NOT EXISTS (SELECT q.QUESTIONID FROM PSP_QUESTION_MASTER AS q 
        WHERE q.PSPID = qq.PSPID 
        EXCEPT 
        SELECT a.QUESTIONID FROM PSP_ANSWER_MASTER AS a 
        WHERE a.PSPID = qq.PSPID); 
+0

這對我有效......非常感謝:) – SUPERGIRL

相關問題