有沒有辦法添加到二維數組中的下一個可用空間？ （Python 3.x）

Question

Python中是否有方法將數組添加到下一個可用空間？所以如果（0,0）已經有一個值，就移動到（0,1）並在那裏添加值。我得到了如下所示，我現在卡住了..

class Array: 

    def __init__(self): 
     self.array = [[0 for x in range(5)] for x in range(5)] 

    def view(self): 
     for x in self.array: 
      print(x) 

    def input(self): 
     item = input("Enter an item: ") 
     self.array[0][0] = item 

array = Array() 

array.input() 
array.view() 

Answer 1

這裏是一個例子。我只是運行循環9次。您應該能夠將其應用到您的OOP樣式代碼中。我也使用標準庫中的pprint模塊，因爲我喜歡它顯示嵌套列表的方式。 （假設5總是進入）：循環的最後一次迭代之後

from pprint import pprint as pp 


myList = [[0 for x in range(5)] for x in range(5)] 

for i in range(9): 
    userInput = int(input("Enter an item: ")) 
    isFound = False # This flag is used to prevent duplicate entries. 

    for rowIndex, row in enumerate(myList): 
     for colIndex, column in enumerate(row): 
      if column == 0 and not isFound: 
       myList[rowIndex][colIndex] = userInput 
       isFound = True 
       break 
    pp(myList) 

輸出

Enter an item: 5 
[[5, 5, 5, 5, 5], 
[5, 5, 5, 5, 0], 
[0, 0, 0, 0, 0], 
[0, 0, 0, 0, 0], 
[0, 0, 0, 0, 0]] 

Answer 2

class Array: 

    def __init__(self): 
     self.myList = [[0 for x in range(5)] for x in range(5)] 

    def input(self): 
     print("You will be asked to put a value, if you want to stop, press RETURN key.") 
     for i in range(25): 
      print() 
      userInput = input("Enter an item: ") 
      isFound = False 


      if userInput == '': 
       menu() 

      for rowIndex, row in enumerate(self.myList): 
       for colIndex, column in enumerate(row): 
        if column == 0 and not isFound: 
         self.myList[rowIndex][colIndex] = userInput 
         isFound = True 
         break 


      print() 
      for x in self.myList: 
       print(x) 

    def remove(self): 
     print("Which box do you want to delete? Type in coordinates.") 
     x = int(input("Please enter a column: ")) 
     x -= 1 
     y = int(input("Please enter a row: ")) 
     y -= 1 
     self.myList[x][y] = 0 
     print() 
     for i in self.myList: 
      print(i) 
     menu() 

    def view(self): 
     for i in self.myList: 
      print(i) 
     menu() 



array = Array() 

def menu(): 
    print() 
    print() 
    print() 
    print("****************") 
    print("  MENU") 
    print("****************") 
    print("Please choose:") 
    print("1. Add an item to the array") 
    print("2. Remove an item from the array") 
    print("3. View array") 
    print() 
    print("0. Quit") 
    print("****************") 
    option = int(input("Enter (1, 2 or 0): ")) 
    print() 
    if option == 1: 
     array.input() 
    elif option == 2: 
     array.remove() 
    elif option == 3: 
     array.view() 
    elif option == 0: 
     quit() 
    else: 
     print("Error..") 


menu()