使用代碼點火器的SQL查詢

Question

如何將此查詢寫入代碼點火器查詢？

WHERE 
    SmallVersion.ID = 
    (
    SELECT ChildSmallVersionID AS ID FROM SmallVersion 
    WHERE ID = $id 
) 

這是怎麼看起來這麼遠：

  ->where('SmallVersion.ID', ("SELECT `ChildSmallVersionID` AS ID 
        FROM `SmallVersion` WHERE ID = $id")); 

Answer 1

Mateusz Wojtula的答案看起來不錯，但你可以保護你的查詢

$strSubQuery = $this->db 
    ->select("ChildSmallVersionID AS ID") 
    ->from("SmallVersion") 
    ->where("ID",$id) 
    ->get_compiled_select(); 

$where = "SmallVersion.ID = (".$strSubQuery.")"; 
$this->db->where($where, NULL, FALSE); 

Answer 2

有沒有可能創造活動記錄括號，但你可以把它直接在子句中寫：

$where = "SmallVersion.ID = 
    (
    SELECT ChildSmallVersionID AS ID FROM SmallVersion 
    WHERE ID = $id 
)"; 
$this->db->where($where, NULL, FALSE); 

如果第三個參數設置爲FALSE，CodeIgniter不會保護您的查詢。

的文檔的活動記錄： https://www.codeigniter.com/user_guide/database/query_builder.html#looking-for-specific-data