我嘗試模仿Drupal 7在Java中檢查正確密碼的方式。 在這裏找到一些代碼作爲指導:https://github.com/CraftFire/AuthDB-Legacy/blob/master/src/main/java/com/authdb/scripts/cms/Drupal.java並提取我需要的代碼。Drupal密碼的Java驗證
但是,當我給密碼和散列版本(爲了提取所需的鹽量和迭代量),我得到了不同的結果。
使用Drupal的密碼哈希腳本 導致生成的密碼:
Expected value = $S$DxVn7wubSRzoK9X2pkGx4njeDRkLEgdqPphc2ZXkkb8Viy8JEGf3
Calculated value = $S$DxVn7wubSpQ1CpUnBZZHNqIXMp2XMVZHMYBqAs24NsUHMY7HBkYn
Expected value = $S$DOASeKfBzZoqgSRl/mBnK06GlLESyMHZ81jyUueEBiCrkkxxArpR
Calculated value = $S$DOASeKfBzs.XMVZ1NkYXNmIqMpEHAoEaMYJ1NmUHCZJaBZFnAZFX
任何人能幫助我/告訴我什麼,我做錯了什麼? 謝謝。
代碼:
import java.io.UnsupportedEncodingException;
import java.security.MessageDigest;
import java.security.NoSuchAlgorithmException;
class test {
public static void main(String args[]) {
// Passwords and hashes generated by Drupal.
checkPassword("test" , "$S$DxVn7wubSRzoK9X2pkGx4njeDRkLEgdqPphc2ZXkkb8Viy8JEGf3");
checkPassword("barbaz", "$S$DOASeKfBzZoqgSRl/mBnK06GlLESyMHZ81jyUueEBiCrkkxxArpR");
}
private static String itoa64 = "./ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz";
private static final int DRUPAL_HASH_LENGTH = 55;
private static int password_get_count_log2(String setting) { return itoa64.indexOf(setting.charAt(3)); }
/**
* Note: taken from the default Drupal 7 password algorithm
* @param candidate
* the clear text password
* @param saltedEncryptedPassword
* the salted encrypted password string to check => NEEDS TO BE THE DEFAULT DRUPAL 7 PASSWORD HASH.
* @return true if the candidate matches, false otherwise.
*/
public static boolean checkPassword(String candidate, String saltedEncryptedPassword) {
if (candidate == null) {
return false;
}
if (saltedEncryptedPassword == null) {
return false;
}
String hash = password_crypt(candidate, saltedEncryptedPassword);
System.out.println("Tested value = " + saltedEncryptedPassword);
System.out.println("Calced value = " + hash);
return hash == saltedEncryptedPassword;
}
public static String SHA512(String text) {
byte[] sha1hash = new byte[40];
try {
MessageDigest md = MessageDigest.getInstance("SHA-512");
md.update(text.getBytes("UTF-8"), 0, text.length());
sha1hash = md.digest();
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
return convertToHex(sha1hash);
}
private static String convertToHex(byte[] data) {
StringBuffer buf = new StringBuffer();
for (int i = 0; i < data.length; i++) {
int halfbyte = (data[i] >>> 4) & 0x0F;
int two_halfs = 0;
do {
if ((0 <= halfbyte) && (halfbyte <= 9))
buf.append((char) ('0' + halfbyte));
else
buf.append((char) ('a' + (halfbyte - 10)));
halfbyte = data[i] & 0x0F;
}
while(two_halfs++ < 1);
}
return buf.toString();
}
private static String password_crypt(String password, String setting) {
// The first 12 characters of an existing hash are its setting string.
setting = setting.substring(0, 12);
int count_log2 = password_get_count_log2(setting);
String salt = setting.substring(4, 12);
// Hashes must have an 8 character salt.
if (salt.length() != 8) {
return null;
}
// Convert the base 2 logarithm into an integer.
int count = 1 << count_log2;
String hash;
try {
hash = SHA512(salt + password);
do {
hash = SHA512(hash + password);
} while (--count >= 0);
} catch(Exception e) {
return null;
}
int len = hash.length();
String output = setting + password_base64_encode(hash, len);
return (output.length() > 0) ? output.substring(0, DRUPAL_HASH_LENGTH) : null;
}
private static String password_base64_encode(String input, int count) {
StringBuffer output = new StringBuffer();
int i = 0, value;
do {
value = input.charAt(i++);
output.append(itoa64.charAt(value & 0x3f));
if (i < count) {
value |= input.charAt(i) << 8;
}
output.append(itoa64.charAt((value >> 6) & 0x3f));
if (i++ >= count) {
break;
}
if (i < count) {
value |= input.charAt(i) << 16;
}
output.append(itoa64.charAt((value >> 12) & 0x3f));
if (i++ >= count) {
break;
}
output.append(itoa64.charAt((value >> 18) & 0x3f));
} while (i < count);
return output.toString();
}
}
- PS。 有一件事我已經看到的是以下內容: 考慮以下功能:
public String convertToHex(byte[] data) {
StringBuffer buf = new StringBuffer();
for (int i = 0; i < data.length; i++) {
int halfbyte = (data[i] >>> 4) & 0x0F;
int two_halfs = 0;
do {
if ((0 <= halfbyte) && (halfbyte <= 9))
buf.append((char) ('0' + halfbyte));
else
buf.append((char) ('a' + (halfbyte - 10)));
halfbyte = data[i] & 0x0F;
}
while(two_halfs++ < 1);
}
return buf.toString();
}
和
public String convertToHex(byte [] raw) {
StringBuilder hex = new StringBuilder(2 * raw.length);
for (final byte b : raw) {
int hiVal = (b & 0xF0) >> 4;
int loVal = b & 0x0F;
hex.append((char) ('0' + (hiVal + (hiVal/10 * 7))));
hex.append((char) ('0' + (loVal + (loVal/10 * 7))));
}
return hex.toString();
}
第一個函數返回字符串爲小寫,二是返回更高的情況下字符串。不知道使用哪一個,最終都返回不同的結果,但都不令人滿意。
CNC中
幾乎有??? ...
來到了一步,改變有點... 在Drupal是使用了以下功能的問題:
$hash = hash($algo, $salt . $password, TRUE);
返回
'���Y�emb
ӈ3����4��q����h�osab��V�!IS�uC�*[�
正如你看到的,我們不需要十六進制版本,因爲你會得到一個總不同的哈希回來...... 所以我改變了代碼Java中:
public byte[] SHA512(String text) {
byte[] sha1hash = new byte[50];
try {
MessageDigest md = MessageDigest.getInstance("SHA-512");
md.update(text.getBytes("UTF-8"), 0, text.length());
sha1hash = md.digest();
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
return sha1hash;
}
--snip--
hash = new String(SHA512(salt + password));
System.out.println(hash);
返回:
'���Y�emb
ӈ3����4��q���h�osab��V�!IS�uC�*[�
正如你看到的,多數民衆贊成幾乎相同....
php: ӈ3����4��q����h�osab��V�!IS�uC�*[�
java: ӈ3����4��q���h�osab��V�!IS�uC�*[�
任何人都有線索如何解決最後一部分? 表單新字符串(SHA512(鹽+密碼,'Whatevercodec'));沒有幫助我... 謝謝!
這奇妙的作品!謝謝! – 2013-06-25 10:02:03
完美!謝謝! – mykola 2016-04-14 21:41:29