MySQL根據同一列中的兩個不同值找到結果

列出僱員姓名（Ename），他們同時擁有49008個郵政編碼客戶和49009個郵政編碼客戶。MySQL根據同一列中的兩個不同值找到結果

我很努力回答基於上述表格的上述查詢。

如果表之間的名稱匹配假定約束。

我可以通過左連接和羣組輕鬆地過濾到名稱和zip，但之後掙扎，我不知道適當的地方或有聲明。我假設它可以通過子查詢做得更好，但不能確定。理想情況下，一個查詢。

請謝謝。

1）創建並插入例如數據的語句：

Create table Employees (EM_Eno INT NOT NULL, EM_Ename VARCHAR(50), EM_Hire_Date DATE, PRIMARY KEY(EM_Eno)); 

Create table Customers (Customers_Cno INT NOT NULL, Customers_Cname VARCHAR(50), Customers_Street VARCHAR(50), Customers_Zip INT, Customers_Phone INT, primary key(Customers_Cno)); 

Create table Orders (Orders_Ono INT NOT NULL, Orders_Cno INT, Orders_Eno INT, Orders_Received DATE, Orders_Shipped DATE, primary key(Orders_Ono)); 


insert into Orders values 
(1,301,501,20161010,20161011); 
(2,302,501,20161011,20161012); 
(3,303,502,20161110,20161111); 
(4,304,502,20161110,20161112); 
(5,305,502,20161110,20161113); 
(6,306,503,20161112,20161114); 
(7,307,501,20161112,20161113); 
(8,308,503,20161112,20161115); 
(9,309,503,20161115,20161120); 
(10,300,501,20161112,20161113); 

insert into Customers values 
(300,'Bryan','100 street',49009,1234567890), 
(301,'Ryan','101 street',49008,1234567890), 
(302,'Nick','102 street',49009,1234567890), 
(303,'Nicholas','103 street',49009,1234567890), 
(304,'Alexa','104 street',49009,1234567890), 
(305,'Tori','105 street',49008,1234567890), 
(306,'Scarlet','106 street',49008,1234567890), 
(307,'Heather','100 street',49009,1234567890), 
(308,'Amanda','107 street',49008,1234567890), 
(309,'James','108 street',49008,1234567890); 

insert into Employees values 
(501,'Robert',20041010), 
(502,'Sam',20050110), 
(503,'Brandy',20050710);

2）理想的最終結果是回答查詢「列表的員工誰同時擁有49008拉鍊碼客戶和49009拉鍊碼客戶（名稱）。」

3）最佳嘗試迄今：

select Employees.EM_Ename 
    , Customers.Customers_Zip 
    from Employees 
    left 
    join Orders 
    on Employees.EM_Eno = Orders.Orders_Eno 
    left 
    join Customers 
    on Orders.Orders_Cno = Customers.Customers_Cno 
group 
    by Employees.EM_Ename 
    , Customers.Customers_Zip;

來源

2017-01-30 Bryan Birchmeier

感謝您對如何正確地請求指導。我相信我提供了一個更明確的要求。讓我知道如果它仍然不清楚。 –

其中是針對行集返回的值的過濾器，具有針對組對列的過濾器。 – Edward

名在rextest稍有改變，因爲其他表已經具有相同名稱的存在有表...

SELECT e.* 
    FROM tbl_employees e 
    JOIN tbl_orders o 
    ON o.orders_eno = e.em_eno 
    JOIN tbl_customers c 
    ON c.Customers_Cno = o.Orders_Cno 
WHERE c.Customers_Zip IN(49008,49009) 
GROUP 
    BY e.em_eno 
HAVING COUNT(DISTINCT customers_zip) = 2;

http://rextester.com/HCNLU51847

來源

2017-01-30 10:30:04 Strawberry

這應該是你想要什麼：

select Min(e.Ename) 
from #Employees e 
join #Orders o on o.Eno = e.Eno 
join #Customers c on c.Cno = o.Cno 
join #Orders o2 on o2.Eno = e.Eno 
join #Customers c2 on c2.Cno = o2.Cno 
where o.Ono !=o2.Ono--c.Cno != c2.Cno and 
and c.Zip = 49008 and c2.Zip = 49009 
group by e.Ename,c.Zip 
order by e.Ename

正如你可以看到，如果你想比這兩個自聯接變得更長了。

來源

2017-01-30 03:17:49 Edward

MySQL根據同一列中的兩個不同值找到結果

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