我有動態的報表名稱按鈕,每次用戶點擊按鈕時,都會顯示適用於所有報表的搜索字段(開始日期,結束日期),所有報表有他們不同的頁面顯示自己的網格,現在我怎樣才能傳遞參數並打開報告的相應頁面並加載jqgrid。我已經通過這個傳遞參數進入「OnlineSales」頁面,然後加載網格。預先感謝您的幫助!如何從其他頁面傳遞參數到jqgrid
我點擊搜索按鈕後,將調用OnlineSales頁面並傳遞參數,然後在網格中顯示數據的語法。
$('#SearchButton').click(function() {
var _StartDate = $("#StartDate").val();
var _EndDate = $("#EndDate").val();
});
呼叫OnlineSales查看與參數
@{
ViewBag.Title = "OnlineSales";
}
@*GRID*@
<div id="table" class="table">
<table id="List" class="scroll" cellpadding="0" cellspacing="0"></table>
<div id="Pager" class="scroll" style="text-align:center;"></div>
</div>
@*GRID*@
<script type="text/javascript">
jQuery(document).ready(function() {
jQuery("#List").jqGrid({
url: 'local',
postData: { start_date: '', end_date: ''},
datatype: "json",
mtype: 'GET',
colNames: [
'First Name',
'Middle Name',
'Last Name',
'Email',
'Mobile Number'],
colModel: [
{ name: 'FirstName', index: 'FirstName', width: 200, align: 'left' },
{ name: 'MiddleName', index: 'MiddleName', width: 200, align: 'left' },
{ name: 'LastName', index: 'LastName', width: 150, align: 'left' },
{ name: 'Email', index: 'Email', width: 150, align: 'left' },
{ name: 'MobileNumber', index: 'MobileNumber', width: 80, align: 'left' }],
pager: jQuery('#Pager'),
rowNum: 10,
rowList: [5, 10, 20, 50, 100],
sortname: 'FirstName',
width: '1005',
sortorder: "asc",
sorttype: 'int',
viewrecords: true,
height: 'auto',
shrinkToFit: false,
cache: false,
caption: 'Online Sales'
});
jQuery("#List").jqGrid('navGrid', '#Pager', { edit: false, add: false, del: false, search: false, refresh: true });
});
</script>
我的控制器
public ActionResult OnlineSales(string sidx, string sord, int page, int rows, DateTime start_date, DateTime end_date)
{
_DashboardDataAccess = new DashboardDataAccess(0);
List<OnlineSales> _OnlineSales = _DashboardDataAccess.OnlineSales(start_date, end_date);
var result = _OnlineSales.AsQueryable().AsEnumerable<OnlineSales>();
int count = result.Count();
result = result.Skip((page - 1) * rows).Take(rows);
int pagecount = (count % rows) == 0 ? (count/rows) : (count/rows) + 1;
var ReportList = (from r in result
select new
{
cell = new string[] {
r.FirstName,
r.MiddleName,
r.LastName,
r.Email,
r.MobileNumber
}
});
var jsonData = new
{
total = pagecount,
page = page,
records = count,
rows = ReportList.ToArray()
};
return Json(jsonData, JsonRequestBehavior.AllowGet);
}
謝謝你但我不能顯示OnlineSales頁面數據 – naru