在Django EmailMessage中傳遞Tuple作爲'To'參數的錯誤

Question

嘗試發送電子郵件時，我給出'To'參數一組電子郵件地址時出現以下錯誤。

> TypeError: sequence item 0: expected 
> string, tuple found 

我已經看過Django文檔的EmailMessage class，它表明這應該是罰款。任何人有什麼可能會出錯的建議？

我構建EmailMessage對象，像這樣：

spam = EmailMessage("Some title - %s \"%s\"" % (subject, task.name), message, 
           "%s <%s>" % (user.get_full_name(), user.email), settings.MAIL_LIST) 
spam.content_subtype = "html" 
spam.send() 

和

settings.MAIL_LIST = ["foo@bar.com", "foo2@bar.com", "foo3@bar.com"] 

部分堆棧跟蹤：

> File "/myClass/Mail.py", line 217, in 
> contact_owner 
>  spam.send() 
> 
> File 
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py", 
> line 281, in send 
>  return self.get_connection(fail_silently).send_messages([self]) 
> 
> File 
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py", 
> line 185, in send_messages 
>  sent = self._send(message) 
> 
> File 
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py", 
> line 199, in _send 
>  email_message.message().as_string()) 
> 
> File 
> "/port/python-environments/port_web/lib/python2.6/site-packages/django/core/mail.py", 
> line 253, in message 
>  msg['To'] = ', '.join(self.to) 
> 
> TypeError: sequence item 0: expected 
> string, tuple found 

Answer 1

這最終是一個非問題，因爲我上面的信息實際上是不正確的。我的錯誤幾乎是錯誤信息描述的。我將字符串電子郵件地址列表傳遞給想要元組列表的代碼。

Answer 2

發送HTML電子郵件例如

from django.core.mail import EmailMultiAlternatives 
from django.utils.html import strip_tags 

subject = render_to_string('cart/email/order_subject.txt',c) 
html_body = t.render(Context(c)) 
text_body = strip_tags(html_body) 

msg = EmailMultiAlternatives(subject, text_body, None, sc.settings['email_order'].split(',')) 
msg.attach_alternative(html_body, "text/html") 
msg.send()