獲取JavaScript數組中的對象其中appointmentments.id = calEvent.id

Question

如何獲取appointments數組中的對象，其中appointments.id = calEvent.id？

appointments.push({ 
    id: id, 
    start: startFormatted, 
    end: endFormatted, 
    title: '<b>' + title + '</b><br><div id="event_body">' + body + '</div>', 
    userId: userid, 
    categoryId: categoryId, 
    counterId: counter 
}); 

eventRender : function(calEvent, $event) { 
    var id = calEvent.id; 

    // get the object in the appointments-array where appointments.id = calEvent.id 
} 

Answer 1

您需要遍歷您appointments陣列的找到匹配id。試試這個：

eventRender : function(calEvent, $event) { 
    var id = calEvent.id;   
    for (var i = 0; i < appointments.length; i++) { 
     if (appointments[i].id == id) { 
      // do something with the appointment... 
      break; 
     } 
    } 
} 

Answer 2

你只需通過數組，尋找想要的ID必須循環：

for (var i = 0; i < appointments.length; i++) { 
    if (appointments[i].id == calEvent.id) { 
     // appointments[i] contains the desired id 
     break; 
    } 
} 

Answer 3

怎麼樣

appointments[id]={ 

    start: startFormatted, 
    end: endFormatted, 
    title: '<b>' + title + '</b><br><div id="event_body">' + body + '</div>', 
    userId: userid, 
    categoryId: categoryId, 
    counterId: counter 
}; 

然後

eventRender : function(calEvent, $event) { 
    var id = calEvent.id; 
    // get the object in the appointments-array where appointments.id = calEvent.id 
    var obj=appointments[id] 
} 

差指數總是比挑剔循環&推快也慢 編輯添加的，如果你不能改變你建立你的約會的方式，你仍然可以通過它循環一次來創建一個索引數組，以供你的eventrender函數使用，這將更有效率比每循環一次eventrender更有效。您的約會最大，最需要明確索引