TypeError：'int'類型的參數不是可迭代的python 2.7

Question

我正在編寫一個解決數獨遊戲的腳本，我最初只是爲9x9創建它，現在將它擴展到任何數獨遊戲。該腳本在4x4和9x9上工作，但是當我給它一個16x16的時候，它返回TypeError：類型'int'的參數不是可迭代的python 2.7在第38行，'if if in dic [entry]：dic [entry] .remove（i ）」

繼承人我的代碼

from math import sqrt 
def sudoku(puzzle): 
    n = len(puzzle) 
    # Builds Dictionary with board position and value 
    dic = {str(i+1) + '-' + str(j+1): puzzle[i][j] for i in xrange(0, n) for j in xrange(0, n)} 
    # Builds list of each possible value for all empty (0) spaces, only considers row and column possibilities 
    while 0 in dic.values(): 
     for entry in dic: 
      if dic[entry] == 0: 
       temp1 = [] 
       temp2 = [] 
       for entry1 in dic: 
        if entry1[0] == entry[0]: temp1.append(dic[entry1]) 
        if entry1[-1] == entry[-1]: temp1.append(dic[entry1]) 
       for i in xrange(1, n+1): 
        if i not in temp1: temp2.append(i) 
       dic[entry] = temp2 
    # populates dictionary with invalid spaces in each square 
     sqrdic = {str(i)+str(j): [] for i in xrange(1, int(sqrt(n))+1) for j in xrange(1, int(sqrt(n))+1)} 
     for entry in dic: 
      if len(str(dic[entry])) == 1: 
       for index in xrange(1, int(n/sqrt(n)+1)): 
        if (index-1)*sqrt(n) < int(entry[0]) <= index*sqrt(n): 
         for index2 in xrange(1, int(sqrt(n))+1): 
          if (index2-1)*sqrt(n) < int(entry[-1]) <= index2*sqrt(n): 
           sqrdic[str(index) + str(index2)].append(dic[entry]) 
     # Removes invalid choices based on values in the square 
     for entry in dic: 
      if len(str(dic[entry])) > 1: # only looking at spaces with multiple possible values 
       for index in xrange(1, int(n/sqrt(n)+1)): 
        if (index-1)*sqrt(n) < int(entry[0]) <= index*sqrt(n): 
         for index2 in xrange(1, int(sqrt(n))+1): 
          if (index2-1)*sqrt(n) < int(entry[-1]) <= index2*sqrt(n): 
           for i in sqrdic[str(index)+str(index2)]: 
            if i in dic[entry]: dic[entry].remove(i) 
     # Looks for any space whose possibilities have been reduced to one and replaces the list with that value 
     # All unsolved spaces are then set back to 0 
     for entry in dic: 
      if type(dic[entry]) is list and len(dic[entry]) == 1: 
       dic[entry] = int(dic[entry][0]) 
      elif type(dic[entry]) is list and len(dic[entry]) > 1: dic[entry] = 0 
    solution = [[dic[str(j)+"-"+str(i)] for i in xrange(1,n+1)] for j in xrange(1,n+1)] 
    for line in solution: print line 

和繼承人兩個測試難題，提前

sudoku([[1,0,0,2,3,4,0,0,12,0,6,0,0,0,7,0], 
     [0,0,8,0,0,0,7,0,0,3,0,0,9,10,6,11], 
     [0,12,0,0,10,0,0,1,0,13,0,11,0,0,14,0], 
     [3,0,0,15,2,0,0,14,0,0,0,9,0,0,12,0], 
     [13,0,0,0,8,0,0,10,0,12,2,0,1,15,0,0], 
     [0,11,7,6,0,0,0,16,0,0,0,15,0,0,5,13], 
     [0,0,0,10,0,5,15,0,0,4,0,8,0,0,11,0], 
     [16,0,0,5,9,12,0,0,1,0,0,0,0,0,8,0], 
     [0,2,0,0,0,0,0,13,0,0,12,5,8,0,0,3], 
     [0,13,0,0,15,0,3,0,0,14,8,0,16,0,0,0], 
     [5,8,0,0,1,0,0,0,2,0,0,0,13,9,15,0], 
     [0,0,12,4,0,6,16,0,13,0,0,7,0,0,0,5], 
     [0,3,0,0,12,0,0,0,6,0,0,4,11,0,0,16], 
     [0,7,0,0,16,0,5,0,14,0,0,1,0,0,2,0], 
     [11,1,15,9,0,0,13,0,0,2,0,0,0,14,0,0], 
     [0,14,0,0,0,11,0,2,0,0,13,3,5,0,0,12]]) 

sudoku([[0,0,0,6,0,5,9,4,7], 
     [4,7,2,8,0,9,6,1,5], 
     [0,0,9,1,0,4,8,0,0], 
     [1,2,4,0,5,8,0,0,0], 
     [7,3,8,2,9,6,1,5,4], 
     [0,0,0,3,4,1,2,7,8], 
     [0,0,7,9,0,3,5,0,0], 
     [5,9,1,4,0,2,7,8,3], 
     [3,8,6,5,0,7,0,0,0]]) 

感謝

Answer 1

你的問題是從這一行：

if len(str(dic[entry])) > 1: # only looking at spaces with multiple possible values 

既然您正在做較大的拼圖，一個兩位數的數字將返回True，即使它只有一個值。

我不清楚爲什麼你需要將所有這些東西都轉換爲字符串。在我看來，您可以將它們存儲爲列表，並檢查列表的長度是否大於1.

否則，您可以測試類型是列表還是int。