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我有一種方法是處理要展開的列表和listview中顯示的數據,或者我可以說父項和子項。我如何界面xml文件到我的方法
這裏是prepareListData方法:
private void prepareListData() {
listDataHeader = new ArrayList<String>();
listDataChild = new HashMap<String, List<String>>();
// Adding child data
listDataHeader.add("VRP Medical Bay");
//listDataHeader.add("");
//listDataHeader.add("");
// Adding child data
List<String> listUnderVRP = new ArrayList<String>();
//this is the data that i need to get from my xml service
listUnderVRP.add("eDataClinical");
listUnderVRP.add("Schedule");
listUnderVRP.add("Dictate");
listUnderVRP.add("View Messages");
listUnderVRP.add("Reports for Signature");
listUnderVRP.add("View Billing");
listUnderVRP.add("View State");
listDataChild.put(listDataHeader.get(0), listUnderVRP); // Header, Child data
//listDataChild.put(listDataHeader.get(1), listUnderVRP1);
//listDataChild.put(listDataHeader.get(2), listUnderVRP2);
}
我的問題是,我如何將XML文件集成到這種方法,因爲我想從XML文件得到DATAS,這樣我可以定製我的列表視圖。
我想實現這個代碼:
ArrayList<HashMap<String, String>> songsList = new ArrayList<HashMap<String, String>>();
XMLParser parser = new XMLParser();
String xml = parser.getXmlFromUrl(URL); // getting XML from URL
Document doc = parser.getDomElement(xml); // getting DOM element
NodeList nl = doc.getElementsByTagName(KEY_SONG);
// looping through all song nodes <song>
for (int i = 0; i < nl.getLength(); i++) {
// creating new HashMap
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element) nl.item(i);
// adding each child node to HashMap key => value
map.put(KEY_ID, parser.getValue(e, KEY_ID));
map.put(KEY_TITLE, parser.getValue(e, KEY_TITLE));
map.put(KEY_THUMB_URL, parser.getValue(e, KEY_THUMB_URL));
// adding HashList to ArrayList
songsList.add(map);
}
你將不得不實現一個XML解析器。 –
嗨@DanielBo,你有什麼想法如何實現它? – user3243065