2012-02-09 93 views
0

我在我的PHP腳本中收到分頁錯誤。查詢在mysql工作臺內部直接運行時可以正常工作,並返回正確的結果。PHP分頁查詢失敗

返回錯誤:您的SQL語法錯誤;檢查對應於你的MySQL服務器版本正確的語法使用近「LIMIT 0,20」在行說明書2

$getpositive = "select case_number, c.name as subject, a.name, u.first_name, u.last_name from cases as c join cases_cstm as cc on c.id = cc.id_c 
       left join accounts as a on a.id = c.account_id left join users as u on u.id = c.assigned_user_id where rating_c ='1';"; 
$db -> PS_Pagination($getpositive, 20, 5, ""); 
$db -> setDebug(true); 
$rs = $db->paginate(); 
$positive_rating_rows = mysql_num_rows($rs); 

我然後顯示在一個表中的結果:

while($val = mysql_fetch_assoc($rs)) 
     {   

     ?> 
       </tr> 
       <tr> 
        <td width="7%"><?=$val['case_number']?></td> 
        <td width="40%"><?=$val['subject']?></td> 
        <td width="40%"><?=$val['name']?></td> 
       </tr> 

這裏是我的分頁功能:

public function PS_Pagination($sql, $rows_per_page = 10, $links_per_page = 5, $append = "") { 
    //$this->conn = $connection; 
    $this->sql = $sql; 
    $this->rows_per_page = (int)$rows_per_page; 
    if (intval($links_per_page) > 0) { 
     $this->links_per_page = (int)$links_per_page; 
    } else { 
     $this->links_per_page = 5; 
    } 
    $this->append = $append; 
    $this->php_self = htmlspecialchars($_SERVER['PHP_SELF']); 
    if (isset($_GET['page'])) { 
     $this->page = intval($_GET['page']); 
    } 
} 

public function paginate() { 
    //Check for valid mysql connection 
    if (! $this->IsConnected()) { 
     $this->SetError("No connection"); 
     return false; 
    } 

    //Find total number of rows 
    $all_rs = @mysql_query($this->sql); 
    if (! $all_rs) { 
     if ($this->debug) 
      echo "SQL query failed. Check your query.<br /><br />Error Returned: " . mysql_error(); 
     return false; 
    } 
    $this->total_rows = mysql_num_rows($all_rs); 
    @mysql_close($all_rs); 

    //Return FALSE if no rows found 
    if ($this->total_rows == 0) { 
     if ($this->debug) 
      //echo "Query returned zero rows."; 
     return FALSE; 
    } 

    //Max number of pages 
    $this->max_pages = ceil($this->total_rows/$this->rows_per_page); 
    if ($this->links_per_page > $this->max_pages) { 
     $this->links_per_page = $this->max_pages; 
    } 

    //Check the page value just in case someone is trying to input an aribitrary value 
    if ($this->page > $this->max_pages || $this->page <= 0) { 
     $this->page = 1; 
    } 

    //Calculate Offset 
    $this->offset = $this->rows_per_page * ($this->page - 1); 

    //Fetch the required result set 
    //echo $this->sql . " LIMIT {$this->offset}, {$this->rows_per_page}"; 
    $rs = @mysql_query($this->sql . " LIMIT {$this->offset}, {$this->rows_per_page}"); 
    if (! $rs) { 
     if ($this->debug) 
      echo "Pagination query failed. Check your query.<br /><br />Error Returned: " . mysql_error(); 
     return false; 
    } 
    return $rs; 
} 
+1

發佈實際的錯誤消息可能會有所幫助...還有,您的$ db類(特別是PS_Pagination和paginate函數)的摘錄會有所幫助。 – Oldskool 2012-02-09 21:30:06

+0

我添加了錯誤。我不確定分頁函數的位置。 – ipengineer 2012-02-09 21:33:06

+0

顯然其中一個功能是修改您的查詢(至少添加了「LIMIT 0,20」位),所以看到該功能對此負責至關重要。否則,我們不可能想出一個解決方案。 – Oldskool 2012-02-09 21:37:20

回答

1

你有一個;在查詢結束,然後你想添加LIMIT 0,20到底。所以它看起來像這樣:blah blah blah where something=value; LIMIT 0,20。這不起作用。刪除;進行修復。

請注意,您可能會對SQL_CALC_FOUND_ROWS語法感興趣,因爲這將極大地優化您的分頁方法。

+0

謝謝!我知道它最終會變成一些愚蠢的東西。 – ipengineer 2012-02-09 22:10:27

1

您的SQL語句末尾有分號。我猜方法只是將LIMIT 0, 20附加到您的查詢中,所以它出現如SELECT blah blah; LIMIT 0, 20,這是無效的SQL。