PHP日期範圍檢查

Question

我有2個日期範圍

[contract_start_date] => 2011-10-20 [contract_end_date] => 2011-10-29 

，我想驗證是否低於日期日期範圍內的範圍以上

2011-05-05 and 2011-10-10 

給出的日期，不得以任何方式超出合同範圍

在PHP中是否有這樣的功能？

Answer 1

見:: http://php.net/manual/en/datetime.diff.php

$datetime1 = new DateTime('2011-10-20'); 
$datetime2 = new DateTime('2011-10-29'); 

//PHP 5.3.0 
$interval = $datetime1->diff($datetime2); 
echo $interval->format('%R%a days'); 

//PHP 5.2.2 
var_dump($datetime1 < $datetime2); 

$datetime3 = new DateTime('2011-05-05'); 
$datetime4 = new DateTime('2011-10-10'); 

if ($datetime3 > $datetime1 && $datetime2 > $datetime1 && $datetime3 < $datetime2 && $datetime2 < $datetime2) { 
    //valid range 
}//end if 

Answer 2

$start = strtorime($contract_start_date); 
$end = strtotime($contract_end_date); 

$required_start = strtotime("2011-05-05"); 
$required_end = strtotime("2011-10-10"); 

if ($end > $required_end or $end < $required_start) 
{ 
    //out of range 
} 

if ($start < $required_start or $start > $required_end) 
{ 
    //out of range 
} 

Answer 3

這應該給你，你尋找什麼：

define(CONTRACT_START, "2011-10-20"); 
define(CONTRACT_END, "2011-10-29"); 

function checkDateRange($dateArray) 
{ 
    foreach($dateArray as $dateStr) 
    { 
     $curDate = strtotime($dateStr); 
     if($curDate < strtotime(CONTRACT_START) || $curDate > strtotime(CONTRACT_END)) 
     { 
      return false; 
     } 
    } 
    return true; 
} 


$dates = array(0 => "2011-10-02", 1 => "2011-10-25"); 

if(checkDateRange($dates)) 
{ 
    echo "Dates are within range"; 
} 
else 
{ 
    echo "Dates are NOT within range"; 
} 

Answer 4

找到下面的代碼，以獲得天的時間差，月和年：

<?php 
function datediff($date1,$date2,$format='d'){ 
    $difference = abs(strtotime($date2) - strtotime($date1)); 
    switch (strtolower($format)){ 
    case 'd': 
     $days = round((($difference/60)/60)/24,0); 
     break; 
    case 'm': 
     $days = round(((($difference/60)/60)/24)/30,0); 
     break; 
    case 'y': 
     $days = round(((($difference/60)/60)/24)/365,0); 
     break; 
    } 
    return $days; 
} 
//Example 
echo datediff('2011-06-1','2010-8-30','D') . ' Days<br />'; 
echo datediff('2011-06-1','2010-8-30','m') . ' Months<br />'; 
echo datediff('2011-06-1','2010-8-30','y') . ' Years<br />'; 
?>