PHP，Mysql插入

我試圖做一個星級評分系統，我無法將結果插入到MySQL中。我錯過了一些東西，但我不知道是什麼。我會告訴你我的代碼，也許你可以看看問題在哪裏。在此先感謝！PHP，Mysql插入

首先，我的表格：

<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0 Transitional//EN' 'http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd'> 
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> 
<head> 
<script src='jquery.js' type="text/javascript"></script> 
<script src='documentation/documentation.js' type="text/javascript"></script> 
<link href='documentation/documentation.css' type="text/css" rel="stylesheet"/> 
<script type="text/javaScript" src="documentation/chili/jquery.chili-2.0.js"></script> 
<script type="text/javascript">try{ChiliBook.recipeFolder="documentation/chili/"}catch(e){}</script> 
<script src='jquery.MetaData.js' type="text/javascript" language="javascript"></script> 
<script src='jquery.rating.js' type="text/javascript" language="javascript"></script> 
<link href='jquery.rating.css' type="text/css" rel="stylesheet"/> 
</head> 

<body> 
<div id="tab-Testing"> 
<script> 
$('form1').submit(function() { 
var ans=$(this).serialize(); 
    $.ajax({ 
    type: "POST", 
    url: "starsubmit.php", 
    data:ans 
}).done(function(msg) { 
alert("Data Saved: " + msg); 
}); 
return false; 
}); 
</script> 

<div class="Clear">&nbsp;</div> 
<form id="form1"> 

     Question 1:bla bla bla 

    <input class="star required" type="radio" name="Question 1" value="1"/> 
    <input class="star" type="radio" name="Question 1" value="2"/> 
    <input class="star" type="radio" name="Question 1" value="3"/> 
    <input class="star" type="radio" name="Question 1" value="4"/> 
    <input class="star" type="radio" name="Question 1" value="5"/> 
    </div> 
    <br/> 
    <div class="Clear"> 

     Question 2:bla bla bla 

    <input class="star required" type="radio" name="Question 2" value="1"/> 
    <input class="star" type="radio" name="Question 2" value="2"/> 
    <input class="star" type="radio" name="Question 2" value="3"/> 
    <input class="star" type="radio" name="Question 2" value="4"/> 
    <input class="star" type="radio" name="Question 2" value="5"/> 
    </div> 
    <br/> 
    <div class="Clear"> 

     Question 3:bla bla bla 

    <input class="star required" type="radio" name="Question 3" value="1"/> 
    <input class="star" type="radio" name="Question 3" value="2"/> 
    <input class="star" type="radio" name="Question 3" value="3"/> 
    <input class="star" type="radio" name="Question 3" value="4"/> 
    <input class="star" type="radio" name="Question 3" value="5"/> 
    </div> 
<br> 
    <div class="Clear"> 

     Question 4:bla bla bla 

    <input class="star required" type="radio" name="Question 4" value="1" /> 
    <input class="star" type="radio" name="Question 4" value="2" /> 
    <input class="star" type="radio" name="Question 4" value="3" /> 
    <input class="star" type="radio" name="Question 4" value="4" /> 
    <input class="star" type="radio" name="Question 4" value="5" /> 
    </div> 
    <br/> 
    <div class="Clear"> 

     Question 5:bla bla bla 

    <input class="star required" type="radio" name="Question 5" value="1"/> 
    <input class="star" type="radio" name="Question 5" value="2"/> 
    <input class="star" type="radio" name="Question 5" value="3"/> 
    <input class="star" type="radio" name="Question 5" value="4"/> 
    <input class="star" type="radio" name="Question 5" value="5"/> 
    </div> 
    <br/> 
    <div class="Clear"> 

     Question 6:bla bla bla 

    <input class="star required" type="radio" name="Question 6" value="1" /> 
    <input class="star" type="radio" name="Question 6" value="2" /> 
    <input class="star" type="radio" name="Question 6" value="3" /> 
    <input class="star" type="radio" name="Question 6" value="4" /> 
    <input class="star" type="radio" name="Question 6" value="5" /> 
    </div> 

    <input type="submit" value="Submit scores!" /> </td> 

</form> 
</body> 
</html>

現在，我的starsubmit.php：

<?php 
$mysql_hostname = "localhost"; 
$mysql_user = "root"; 
$mysql_password = ""; 
$mysql_database = "cosmote"; 
$prefix = ""; 
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Opps some thing went wrong"); 
mysql_select_db($mysql_database, $bd) or die("Opps some thing went wrong"); 
if($_SERVER["REQUEST_METHOD"] == "POST") 
{ 
$question1 = mysql_real_escape_string($_POST['question1']); 
$question2 = mysql_real_escape_string($_POST['question2']); 
$question3 = mysql_real_escape_string($_POST['question3']); 
$question4 = mysql_real_escape_string($_POST['question4']); 
$question5 = mysql_real_escape_string($_POST['question5']); 
$question6 = mysql_real_escape_string($_POST['question6']); 

mysql_query("INSERT INTO answers (q1,q2,q3,q4,q5,q6) VALUES ('$question1','$question2','$question3','$question4','$question5','$question6')"); 
echo "<h1>Thank You !</h1>"; 
} 

?>

最後，我的表：

CREATE TABLE IF NOT EXISTS `answers` (
    `q1` int(3) NOT NULL, 
    `q2` int(3) NOT NULL, 
    `q3` int(3) NOT NULL, 
    `q4` int(3) NOT NULL, 
    `q5` int(3) NOT NULL, 
    `q6` int(3) NOT NULL 
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

來源

2012-11-17 user1820705

使用print _r（$ _ POST）; //知道數據是從或不是從post.check它out.it將打印像數組。 –

關閉：http://php.net/manual/en/function.mysql-query.php **不推薦使用此擴展名（mysql_ *）。相反，MySQLi或PDO_MySQL擴展應該使用** – nu6A

實際上你需要告訴我們什麼是錯誤 - 如果有的話...... 以及在什麼級別或什麼時候你的代碼工作正常.. –

我必須說這應該是：

$('form1').submit(function() { // <------you are not submiting the specific form

這樣的：

$('#form1').submit(function() { // <------ every id should have a '#' in jquery

這可能是問題，如果你能在jQuery的改變你的.done功能

.done(function() { 
    alert("Data Saved"); // try removing the passed param "msg" 
});

來源

2012-11-17 11:22:13 Jai

我試過但不是從這裏:( – user1820705

一個ID有一個「＃」開頭

$('form1').submit(function() {

來源

2012-11-17 11:23:41 Marv

回答

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