爲什麼datetime.utcnow（）和datetime.now（timezone（'UTC'））之間有區別？

Question

正如你可以從下面的代碼片段看到的，兩種方法之間有一個小時的差異。是什麼原因 ？

from datetime import datetime 
from pytz import timezone 
import time 

def timestamp2date(timestamp): 
    # function converts a UTC timestamp into Europe/Zurich Gregorian date 
    DATE_TIME_FORMAT = "%Y-%m-%d %H:%M:%S" 
    utcTimeStamp = datetime.fromtimestamp(int(timestamp)).replace(tzinfo=timezone('UTC')) 
    return utcTimeStamp.astimezone(timezone('Europe/Zurich')).strftime(DATE_TIME_FORMAT) 

timeStampUTC_1 = time.mktime(datetime.utcnow().timetuple()) 
print(timeStampUTC_1) 
print(timestamp2date(timeStampUTC_1)) 
timeStampUTC_2 = time.mktime(datetime.now(timezone('UTC')).timetuple()) 
print(timeStampUTC_2) 
print(timestamp2date(timeStampUTC_2)) 
print(timeStampUTC_2 - timeStampUTC_1) 

# 1504385450.0 
# 2017-09-03 00:50:50 this the right time 
# 1504389050.0 
# 2017-09-03 01:50:50 
# 3600.0 

Answer 1

的原因是，datetime.timetuple()套dst=-1如果datetime沒有偏移量感知和dst=0 or 1當偏移量感知。

從文檔：

結果的tm_isdst標誌根據dst()方法設置：tzinfo是None或dst()返回None，tm_isdst設爲-1;否則，如果dst()返回非零值，則tm_isdst設置爲1;否則tm_isdst設置爲0。

In []: 
datetime.utcnow() 
Out[]: 
datetime.datetime(2017, 9, 2, 23, 9, 12, 715042) 

In []: 
print(datetime.utcnow().dst()) 
Out[]: 
None 

In []: 
datetime.now(timezone('UTC')) 
Out[]: 
datetime.datetime(2017, 9, 2, 23, 9, 15, 856983, tzinfo=<UTC>) 

In []: 
datetime.now(timezone('UTC')).dst() 
Out[] 
datetime.timedelta(0) 

In []: 
datetime(2017, 9, 2, 23, 9, 15, 856983).timetuple() 
Out[]: 
time.struct_time(tm_year=2017, tm_mon=9, tm_mday=2, tm_hour=23, tm_min=9, 
       tm_sec=15, tm_wday=5, tm_yday=245, tm_isdst=-1) 
                  ^^ 
In []: 
datetime(2017, 9, 2, 23, 9, 15, 856983, timezone('UTC')).timetuple() 
Out[]: 
time.struct_time(tm_year=2017, tm_mon=9, tm_mday=2, tm_hour=23, tm_min=9, 
       tm_sec=15, tm_wday=5, tm_yday=245, tm_isdst=0) 
                  ^

這改變了timestamp該time.mktime()生成因爲mktime對待-1未知，並且使用本地時間，所以可以計算dst=1，因此，它們可以是一個1小時不同（3600s）：

In []: 
time.mktime(datetime(2017, 9, 2, 23, 9, 15, 856983).timetuple()) 
Out[]: 
1504411755.0 

In []: 
time.mktime(datetime(2017, 9, 2, 23, 9, 15, 856983, timezone('UTC')).timetuple()) 
Out[]: 
1504415355.0 

Answer 2

這裏的這是我進一步探索與夏令時標誌相關的時區概念的結果。代碼非常簡單。

總結的結果，有處理日期/時間信息的正確方法：

1. 日期/時間對象必須本地化
2. 如果正確本地化，日期/時間對象是否顯示正確的夏令時信息
3. 將您的本地化日期/時間對象轉換爲根據定義的UTC日期/時間對象時會反映這一點DST不可知
4. 當您訪問股票或貨幣歷史記錄時，所有這些考慮事項尤其相關CAL分鐘費率API

代碼：

from datetime import datetime 
from pytz import timezone 
import time 

print("---- Winter time (CET=Central European Time) ----") 
dateStr = "2014-02-28 22:28:15" 
datetimeObjUnlocalized = datetime.strptime(dateStr, "%Y-%m-%d %H:%M:%S") 
print('UNL: ' + datetimeObjUnlocalized.strftime("%Y-%m-%d %H:%M:%S %Z%z")) 
print('  datetimeObjUnlocalized-->tm_isdst=' + str(datetimeObjUnlocalized.timetuple()[8])) 
datetimeObjZH = timezone('Europe/Zurich').localize(datetimeObjUnlocalized) 
print('ZH: ' + datetimeObjZH.strftime("%Y-%m-%d %H:%M:%S %Z%z")) 
print('  datetimeObjZH-->tm_isdst=' + str(datetimeObjZH.timetuple()[8])) 
print("UTC: " + datetimeObjZH.astimezone(timezone('UTC')).strftime("%Y-%m-%d %H:%M:%S %Z%z")) 

print("\n---- Summer time (CEST=Central European Summer Time) ----") 
dateStr = "2014-06-28 22:28:15" 
datetimeObjUnlocalized = datetime.strptime(dateStr, "%Y-%m-%d %H:%M:%S") 
print('UNL: ' + datetimeObjUnlocalized.strftime("%Y-%m-%d %H:%M:%S %Z%z")) 
print('  datetimeObjUnlocalized-->tm_isdst=' + str(datetimeObjUnlocalized.timetuple()[8])) 
datetimeObjZH = timezone('Europe/Zurich').localize(datetimeObjUnlocalized) 
print('ZH: ' + datetimeObjZH.strftime("%Y-%m-%d %H:%M:%S %Z%z")) 
print('  datetimeObjZH-->tm_isdst=' + str(datetimeObjZH.timetuple()[8])) 
print("UTC: " + datetimeObjZH.astimezone(timezone('UTC')).strftime("%Y-%m-%d %H:%M:%S %Z%z"))