一個UITableView是一個UIScrollView包埋，滑動刪除是不行的

Question

我嘗試了很多方法，但沒有得到解決

就我而言，我的看法層次：

UIView 
    UIScrollView 
    LeftContainer + RightContainer 
       (in RihgtContainer) ViewContainer 
             TableView 

我試過這些：

子類化Scrollview和

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event 
{ 
    [self.nextResponder touchesBegan:touches withEvent:event]; 
} 

- (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event 
{ 
    if(!self.dragging) 
    { 
     [self.nextResponder touchesMoved:touches withEvent:event]; 
    } 
} 

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event 
{ 
    [self.nextResponder touchesEnded:touches withEvent:event]; 

}

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer 


innerTableView.scrollEnabled = YES; 
innerTableView.alwaysBounceVertical = NO; 

Answer 1

可以托盤設置delaysTouchesBegan到true您滾動型......喜歡這裏https://stackoverflow.com/a/31040918/1702413

但 .. UITableview從UIScrollView

你應該繼承未嵌入UIWebView或UITableView對象UIScrollView對象https://stackoverflow.com/a/17121582/1702413