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使用以下命令:ffmpeg - 多次寫入相同的幀?
ffmpeg -i test.mp4 -vf "select='not(mod(n,2000))',setpts=N/3/TB" -r 3 output.gif
我寫1幀,每2000,在3FPS GIF文件。
但是,當我看到FFmpeg的輸出也有一些是令人困惑:
speed=0.00997frame= 1 fps=0.7 q=-0.0 size= 1kB time=00:00:00.01
speed=0.00498frame= 1 fps=0.4 q=-0.0 size= 1kB time=00:00:00.01
speed=0.00332frame= 2 fps=0.6 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0847xframe= 2 fps=0.4 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0678xframe= 2 fps=0.4 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0565xframe= 2 fps=0.3 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0968xframe= 3 fps=0.4 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0847xframe= 3 fps=0.4 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0753xframe= 3 fps=0.3 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0678xframe= 4 fps=0.4 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0915xframe= 4 fps=0.3 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0839xframe= 4 fps=0.3 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0774xframe= 4 fps=0.3 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0954xframe= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.089x frame= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.0834xframe= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.0785xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
speed=0.093x frame= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
speed=0.0881xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
speed=0.0837xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
它看起來像每個被重建多次,目標幀。 我希望是這樣的:
speed=0.00997frame= 1 fps=0.7 q=-0.0 size= 1kB time=00:00:00.01
speed=0.00332frame= 2 fps=0.6 q=-0.0 size= 2kB time=00:00:00.34
speed=0.0968xframe= 3 fps=0.4 q=-0.0 size= 20kB time=00:00:00.68
speed=0.0678xframe= 4 fps=0.4 q=-0.0 size= 41kB time=00:00:01.01
speed=0.0954xframe= 5 fps=0.3 q=-0.0 size= 66kB time=00:00:01.34
speed=0.0785xframe= 6 fps=0.3 q=-0.0 size= 90kB time=00:00:01.68
我缺少的東西?
(這是從一個ffmpeg - multiple output with thumbnails隨訪)
好的,我明白了;所以它不會處理多個源幀來更新目標幀。謝謝! – Thomas