如何建立一個查詢「你可能知道的人」

Question

我需要顯示「你可能知道的人」基於用戶的當前朋友和朋友的建議應該考慮阻止用戶，如果用戶A阻止用戶B，A應該不會看到用戶B或反之亦然他們的朋友建議 這裏是我的表結構

mnc_users

id | username | email  | fullname 
--------------------------------------------------- 
1 | userA  | usera@in.in | User Alpha 
2 | userB  | userb@in.in | User Bravo 
3 | userC  | userc@im.in | user c 
4 | userd  | userd@am.in | user del 

mnc_friends

uid | fid | time 
------------------------- 
1 | 3 | 1363859398 
3 | 1 | 1363859398 
4 | 1 | 1368854898 
1 | 4 | 1368854898 
3 | 2 | 1363846116 
2 | 3 | 1363846116 
2 | 4 | 1363846116 
4 | 3 | 1363846116 

mnc_blocked

個

id | uid | bid 
-------------------- 
1 | 1 | 2 

mnc_frnd_rqsts

uid | fid 
----------- 
5 | 1 

我如何使用PHP和MySQL在這種情況下，用戶的建議顯示？

Answer 1

如果u編輯this answer添加幾你會得到它的東西

$user_id = 1; 

    $sql = " SELECT * FROM mnc_users WHERE id NOT IN(
              SELECT fid FROM mnc_friends WHERE uid='$user_id' AND fid!='$user_id' 
              ) 
             AND id NOT IN(
              SELECT bid FROM mnc_blocked WHERE uid='$user_id' 
              ) 
AND id NOT IN(
          SELECT fid FROM mnc_frnd_rqsts WHERE uid='$user_id' 
              ) 
     "; 

Answer 2

試試這個

假設我們正在試圖讓人民爲用戶A：ID = 1

$user_id = 1; 

和SQL將

$sql = " SELECT * FROM mnc_users WHERE id IN(
             SELECT fid FROM mnc_friends WHERE uid='$user_id' AND fid!='$user_id' 
             ) 
            AND id NOT IN(
             SELECT bid FROM mnc_blocked WHERE uid='$user_id' 
             ) 
    ";