的XPath 2個的某些元素

Question

我有這樣的HTML頁面之間選擇元素：

<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="other_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Select this 
<tr class="other_label"></tr> # Select this 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="other_label"></tr> 

我要選擇帶班的TR元素「other_label」這是最後2個TR元素與類「facts_label」之間

我想：

'//tr[@class="other_label" and (preceding-sibling::tr[@class="facts_label"][last()-1]) and (following-sibling::tr[@class="facts_label"][last()])]' 

但是，這是我得到

<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Got this 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Got this 
<tr class="other_label"></tr> # Got this 
<tr class="facts_label"></tr> 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> # Got this 
<tr class="other_label"></tr> # Got this 
<tr class="facts_label"></tr> 
<tr class="other_label"></tr> 
<tr class="other_label"></tr> 

Answer 1

的XPath 「絕招」：

//tr[ @class='other_label' and count(following-sibling::tr[@class='facts_label'])=1 ]