PHP會話陣列添加元素，如果同一ID

的print_r（$ _ SESSION [ '項目']）：

Array 
(
    [0] => Array 
     (
      [p_name] => Product A 
      [p_price] => 13.90 
      [p_seller] => 2001 
     ) 

    [1] => Array 
     (
      [p_name] => Product B 
      [p_price] => 2.00 
      [p_seller] => 2002 
     ) 

    [2] => Array 
     (
      [p_name] => Product C 
      [p_price] => 1.20 
      [p_seller] => 2002 
     ) 

    [3] => Array 
     (
      [p_name] => Product D 
      [p_price] => 50.00 
      [p_seller] => 2001 
     ) 

)

我有一個循環從DB調用額外的數據：

while($res = $shipment->fetch_object()){ 
    $seller_id = $res->seller; 
    $shipment_cost = $res->shipment_fee; 

    //array_push($_SESSION['items']['p_fee'], $shipment_cost); 
}

讓說，在一個循環中，我得到以下數據：

$ seller_id = 2001; $ shipment_cost = 5.00

$ seller_id = 2002; $ shipment_cost = 3.00

我要分配並用名稱['p_fee']添加一個額外的元件到其相應的組['p_seller']

如果$ seller_id（2001）== [ 'p_seller'] ---> array_push（$ _ SESSION ['items'] ['p_fee']，'5.00'）}

if $ seller_id（2002）== ['p_seller'] ---> array_push（$ _ SESSION ['items']] ['p_fee']，'3.00'）}

可以做到這一點嗎？

的$_SESSION['items']最後可能包含如下內容：

Array 
(
    [0] => Array 
     (
      [p_name] => Product A 
      [p_price] => 13.90 
      [p_seller] => 2001 
      [p_fee] => 5.00 
     ) 

    [1] => Array 
     (
      [p_name] => Product B 
      [p_price] => 2.00 
      [p_seller] => 2002 
      [p_fee] => 3.00 
     ) 

    [2] => Array 
     (
      [p_name] => Product C 
      [p_price] => 1.20 
      [p_seller] => 2002 
      [p_fee] => 3.00 
     ) 

    [3] => Array 
     (
      [p_name] => Product D 
      [p_price] => 50.00 
      [p_seller] => 2001 
      [p_fee] => 5.00 
     ) 

)

來源

2017-01-06 Nanny Boy

這似乎是合乎邏輯的我修改2個查詢我假設你正在運行從一個查詢生成該數據。那麼你不需要這樣的小提琴 – RiggsFolly

是的，可以。

您可以通過添加該值，同時從數據庫中檢索該值來實現。例如：

while($res = $shipment->fetch_object()){ 
    $seller_id = $res->seller; 
    $shipment_cost = $res->shipment_fee; 

    foreach ($_SESSION['items'] as $key => $item) { 
     if ($item['p_seller'] === $seller_id) { 
      $_SESSION['items'][$key]['p_fee'] = $shipment_cost; 
     } 
    } 
}

一個更好的（更快）的方式是創建sellerId和成本之間的映射，並隨後將其放在會議：

$costMapping = array(); 
while($res = $shipment->fetch_object()){ 
    $seller_id = $res->seller; 
    $shipment_cost = $res->shipment_fee; 

    $costMapping[$seller_id] = $shipment_cost; 
} 

foreach ($_SESSION['items'] as $key => $item) { 
    if (isset($costMapping[$item['p_seller']])) { 
     $_SESSION['items'][$key]['p_fee'] = $costMapping[$item['p_seller']]; 
    } 
}

這樣，你只需要2個循環，無論你有多少賣家。

來源

2017-01-06 09:47:41 Blaatpraat

是的這可能，你應該只做兩個循環，首先收取費用，其次是將它們與物品相關聯。

// Fill the fees first 
$fees = []; 
while($res = $shipment->fetch_object()){ 
    $seller_id = $res->seller; 
    $shipment_cost = $res->shipment_fee; 
    $fees[$seller_id] = $shipment_fee; 
} 

// Assign fees 
foreach ($_SESSION['items'] as &$item) { 
    $fee = $fees[$item['p_seller']] ?: 0; // <- fee will be 0 if not found ! 
    $item['p_fee'] = $fee; 
}

希望這有助於:)

來源

2017-01-06 09:50:13 webNeat

PHP會話陣列添加元素，如果同一ID

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