注意:我使用ES6(類)什麼可能導致JavaScript「新」關鍵字失敗?
所以我目前工作的一個WinJS通用(UWP)應用程序。我發現大部分時間我的電話(對特定班級)沒有任何問題。但是,當我快速調用它時,返回值就是類本身。我知道引用沒有被改變,因爲我可以在它下面放一個while循環,它會再次開始工作。這似乎是某種時機問題。
我將在下面的代碼破解:
var crop = new $js.Vector2(xCrop, yCrop);
if (!(crop instanceof $js.Vector2)) {
debugger; // This is being hit (not 100% chance, only in rapid use)
}
但是,如果我做了以下內容:
var crop = new $js.Vector2(xCrop, yCrop);
while (!(crop instanceof $js.Vector2)) {
crop = new $js.Vector2(xCrop, yCrop);
}
if (!(crop instanceof $js.Vector2)) {
debugger; // This is never hit and the program continues as normal
}
該計劃將繼續它的正常執行。另外,當我在代碼的這一部分中使用斷點來逐步完成它時,它工作得很好;這導致我相信這是一些時間問題。我只是想弄清楚這是微軟方面還是我方方面的錯誤。
這裏是我的$ js.Vector2代碼:
/**
* A basic 2 dimensional vector
* @class
*/
$js.Vector2 = class {
/**
* @constructor
* @param {number} [x=0] The x dimension of the vector
* @param {number} [y=0] The y dimension of the vector
*/
constructor(x, y) {
/**
* The x dimension of this vector
* @type {number}
*/
this.x = x || 0;
/**
* The y dimension of this vector
* @type {number}
*/
this.y = y || 0;
}
/**
* Copys the x and y dimension of a $js.Vector2 to this one
* @param {number} x
* @param {number} y
*/
set(x, y) {
if (x != null) {
this.x = x;
}
if (y != null) {
this.y = y;
}
}
/**
* Transposes this vector by another vector by shifting (adding)
* @param {$js.Vector2} vector The vector to be added to this vector
*/
move(vector) {
this.x += vector.x;
this.y += vector.y;
}
/**
* Get's the magnitude (pythagorean theorem) of this vector (the length of the hypotenuse of the right triangle produced by this vector)
* @return {number} The length of the hypotenuse
*/
get magnitude() {
return Math.sqrt((this.x * this.x) + (this.y * this.y))
}
/**
* Get's the dot product of this vector and another
* @param {$js.Vector2} vector The vector to be multiplied with this vector
* @return {number} The result of dot product (vector multiplication)
*/
dot(vector) {
return (this.x * vector.x) + (this.y * vector.y);
}
/**
* This will return a new normalized $js.Vector2 of this vector
* @return {$js.Vector2} The normalized $js.Vector2
*/
get normalized() {
var tmp = new $js.Vector2(this.x, this.y);
var mag = this.magnitude;
tmp.x = tmp.x/mag;
tmp.y = tmp.y/mag;
return tmp;
}
/**
* Will get the distance between this vector and another supplied vector
* @param {$js.Vector2} vector
* @return {number} The distance between this $js.Vector2 and the supplied $js.Vector2
*/
distance(vector) {
return Math.sqrt(((vector.x - this.x) * (vector.x - this.x)) + ((this.y - vector.y) * (this.y - vector.y)));
}
/**
* Will subtract this vector from another vector
* @param {$js.Vector2} vector
* @return {$js.Vector2} The result of this vector subtracted by a supplied vector (in that order)
*/
difference(vector) {
return new $js.Vector2((this.x - vector.x), (this.y - vector.y));
}
/**
* Will add this vector from another vector
* @param {$js.Vector2} vector
* @return {$js.Vector2} The result of this vector added by a supplied vector
*/
sum(vector) {
return new $js.Vector2((this.x + vector.x), (this.y + vector.y));
}
/**
* Will check if this vector's components are equal to the supplied vectors
* @param {$js.Vector2} vector The vector to compare against
* @return {boolean} <c>true</c> if the x, y, and z of both vectors are the same value otherwise <c>false</c>
*/
equals(vector) {
if (!(vector instanceof $js.Vector2)) {
return false;
}
return this.x === vector.x && this.y === vector.y;
}
};
任何幫助,將不勝感激。如果可以避免的話,我寧願不需要採取一些黑客辦法來解決這個問題。
編輯:我只是在Surface Pro 3上運行同樣的代碼,它沒有任何問題。這似乎是我的臺式機(英特爾酷睿i7-6700K處理器)的問題。這延續了我作爲一個速度相關問題的假設,將會看到是否有與MS有關的VS的更新/補丁。
'while'循環的預期結果是什麼? – guest271314
@ guest271314「while」循環的目的是爲了證實我的理論,即對'new $ js.Vector2'的調用沒有任何問題。如果我沒有這個調用,程序將在「調試器」上中斷(如圖所示)。但是當我添加這個調用時,它開始工作,我從來沒有打過'debugger'這行。所以通過一次又一次地調用構造函數,它最終將評估一個對象而不是對類/函數的引用。 – baflink
在'difference'和'sum'內調用'new $ js.Vector2'的目的是什麼? – guest271314