如何查找與其他記錄組（關係部門？）匹配的記錄組

Question

爲了設置合併帳戶處理，我想找出 擁有「完全相同」的所有者集合的帳戶。

我認爲這可能會使動態sql支持所有者，然後使用 排名函數，但我不想追求這種方法;我沒有 有多少個名字可以與一個 給定帳戶相關聯，因此我想避免動態SQL。

我的數據（也這是在http://www.sqlfiddle.com/#!3/1d36e）

CREATE TABLE allacctRels 
(account INT NOT NULL, 
module CHAR(3) NOT NULL, 
custCode CHAR(20) NOT NULL) 


INSERT INTO allacctrels 
(account, module, custCode) 
VALUES 
(1, 'DDA', 'Wilkie, Walker'), 
(1, 'DDA', 'Houzemeal, Juvy'), 
(2, 'CDS', 'Chase, Billy'), 
(2, 'CDS', 'Norman, Storm'), 
(3, 'CDS', 'Chase, Billy'), 
(3, 'CDS', 'Norman, Storm'), 
(7, 'CDS', 'Perkins, Tony'), 
(15, 'SVG', 'Wilkie, Walker'), --typo in name before mwigdahl's response 
(16, 'SVG', 'Wilkie, Walker'), -- corrected typo here too 
(606, 'DDA', 'Norman, Storm'), 
(606, 'DDA', 'Chase, Billy'),-- corrected 2nd typo found 
(4, 'LNS', 'Wilkie, Walker'), 
(4, 'LNS', 'Houzemeal, Juvy'), 
(44, 'DDA', 'Perkins, Tony'), 
(222, 'DDA', 'Wilkie, Walker'), 
(222, 'DDA', 'Houzemeal, Juvy'), 
(17, 'SVG', 'Wilkie, Walker'), -- added these three rows in edit, SVG 17 doesn't match any dda 
(17, 'SVG', 'Welch, Raquel'), 
(17, 'SVG', 'Houzemeal, Juvy') 

我想搞清楚，每個模塊科目，什麼最低DDA 帳戶是具有與它相關的完全相同的業主 。

在示例數據中，我想要這些結果，第三列是 擁有相同所有者的最低DDA帳戶。結果應具有相同的行數作爲therea re模塊/帳戶連擊 - 每行每一個行中的「SELECT DISTINCT模塊，帳戶FROM allAcctRels」）

1, DDA, 1 
2, CDS, 606 
3, CDS, 606 
15, SVG, NULL 
16, SVG, NULL 
606, DDA, 606 
4, LNS, 1 
7, CDS, 44 
44, DDA, 44 
222, DDA, 1 
17, SVG, NULL -- added to original post. 

SVG 15和16不匹配任何DDA賬戶，所以 他們互相匹配並沒有關係，他們得到NULL爲帳戶鞏固。 編輯：SVG 17不匹配任何東西，即使有一個DDA acct在SVG 17中擁有所有的持有者，SVG 17中的持有者組合也不會出現任何一個DDA acct。每個DDA帳戶都會自行匹配，除非存在具有相同所有者和較低DDA的 dda帳戶（如DDA 222的情況）。

我可以看到，一種常規方法是將每個帳戶，組 的pivoted表，並使用row_number。鑑於與每個帳戶相關的無限數量的持有者，我認爲這將會花費 動態SQL，我寧願避免。

在我看來，這是一個「關係分區」問題，關係分區可能被CROSS APPLY「饋入」。我試着用 寫一個函數，該函數將一個賬戶持有人的表與一個特定賬戶關聯起來，並找到最低的dda賬戶，沿着下面顯示的行 ，想法是查看給定的所有人數 賬戶與該賬戶加入 給定的dda賬戶的人數相同，但我無法弄清楚如何將 賬戶號碼的表「加入」該功能。

-- this is what I tried but I'm not sure it the logic would work 
-- and I can't figure out how to pass the account holders for each 
-- account in. This is a bit changed from the function I wrote, some 
    -- extraneous fields removed and cryptic column names changed. So it 
    -- probably won't run as is. 

    -- to support a parameter type to a tape 
-- CREATE type VisionCustomer as Table 
-- (customer varchar(30)) 

CREATE FUNCTION consolidatable 
(@custList dbo.VisionCustomer READONLY) 
RETURNS char(10) 
AS 
BEGIN 
DECLARE @retval Varchar(10) 
DECLARE @howmany int 
select @howmany=Count(*) FROM @custlist; 

SELECT @retval = min (acct) FROM allAcctRels 
    JOIN @custlist 
     On VendorCustNo = Customer 
      WHERE acctType = 'DDA' 
      GROUP BY acct 
      HAVING (count(*) = @howmany) 
      and 
      COUNT(*) = (select Count(*) FROM allAcctRels X 
    WHERE X.acctType = 'DDA' 
    AND X.account = AllAcctRels.account) ; 
RETURN @retval 
END; 

Answer 1

如果我理解正確的話，這實際上很簡單。試試這個：

SELECT a.account, a.module, MIN(b.account) 
FROM allacctRels a 
    LEFT JOIN allacctRels b ON a.custCode = b.custCode AND b.module = 'DDA' 
GROUP BY a.account, a.module 

編輯：上面的說明後不工作，但這應該。這確實是一種關係分工。可能不是世界上最有效的查詢計劃，但它有效。

SELECT a.account, a.module, MIN(b.account) 
FROM allacctRels a 
    LEFT JOIN allacctRels b ON b.module = 'DDA' 
    AND 
    -- first test is to confirm that the number of matching names for this combination equals the number of names for the DDA set... 
    (
     SELECT COUNT(*) 
     FROM allacctRels b2 
      INNER JOIN allacctRels a2 ON b2.custCode = a2.custCode 
     WHERE a.account = a2.account AND b.account = b2.account 
    ) = 
    (
     SELECT COUNT(*) 
     FROM allacctRels b2 
     WHERE b.account = b2.account 
    ) 
    AND 
    -- second test is to confirm that the number of names for the DDA set equals the number of names for the base set... 
    (
     SELECT COUNT(*) 
     FROM allacctRels b2 
     WHERE b.account = b2.account 
    ) = 
    (
     SELECT COUNT(*) 
     FROM allacctRels a2 
     WHERE a.account = a2.account 
    ) 
GROUP BY a.account, a.module 

Answer 2

我相信這是你在找什麼（http://www.sqlfiddle.com/#!3/f96c5/1）：

;WITH AccountsWithOwners AS 
(
    SELECT DISTINCT 
    DA.module 
    , DA.account 
    , STUFF((SELECT 
       ',' + AAR.custCode 
       FROM allacctRels AAR 
       WHERE AAR.module = DA.module 
       AND AAR.account = DA.account 
       ORDER BY AAR.custCode 
       FOR XML PATH('')) 
       , 1, 1, '') AS Result 
    FROM allacctRels DA 
) 
, WithLowestDda AS 
(
    SELECT 
     AWO.module 
     , AWO.account 
     , MatchingAccounts.account AS DdaAccount 
     , ROW_NUMBER() OVER(PARTITION BY AWO.module, AWO.account ORDER BY MatchingAccounts.account) AS Row 
    FROM AccountsWithOwners AWO 
    LEFT JOIN AccountsWithOwners MatchingAccounts 
     ON MatchingAccounts.module = 'DDA' 
     AND MatchingAccounts.Result = AWO.Result 
) 
SELECT 
    account 
    , module 
    , DdaAccount 
FROM WithLowestDda 
WHERE Row = 1