json數組格式json_encode php

在我的JavaScript我有這個json工作得很好。json數組格式json_encode php

{ 
    "sEcho": 1, 
    "iTotalRecords": 58, 
    "iTotalDisplayRecords": 58, 
    "aaData": [ 
     ["Gecko","Firefox 1.0","Win 98+/OSX.2+","1.7","A"], 
     ["Gecko","Firefox 1.5","Win 98+/OSX.2+","1.8","A"], 
     ["Gecko","Firefox 2.0","Win 98+/OSX.2+","1.8","A"], 
     ["Gecko","Firefox 3.0","Win 2k+/OSX.3+","1.9","A"], 
     ["Gecko","Camino 1.0","OSX.2+","1.8","A"], 
     ["Gecko","Camino 1.5","OSX.3+","1.8","A"], 
     ["Gecko","Netscape 7.2","Win 95+/Mac OS 8.6-9.2","1.7","A"], 
     ["Gecko","Netscape Browser 8","Win 98SE+","1.7","A"], 
     ["Gecko","Netscape Navigator 9","Win 98+/OSX.2+","1.8","A"], 
     ["Gecko","Mozilla 1.0","Win 95+/OSX.1+","1","A"] 
    ] 
}

但是，這當然是硬編碼，我想使aaData動態。我打算做這樣的事情$就我的PHP有這個代碼

$result = mysql_query("SELECT * FROM Persons"); 

$newArray = array(); 
while($row =mysql_fetch_array($result)){ 
    $newArray[] = $row; 
} 

echo json_encode($newArray);

，並從json_endcode數據是

[ 
{"0":"1","P_Id":"1","1":"zamor","LastName":"zamor","2":"credit","FirstName":"credit","3":"Giftcard","Address":"Giftcard","4":"Finance","City":"Finance"},{"0":"3","P_Id":"3","1":"zamor3","LastName":"zamor3","2":"credit","FirstName":"credit","3":"Giftcard","Address":"Giftcard","4":"Finance","City":"Finance"},{"0":"4","P_Id":"4","1":"zamor4","LastName":"zamor4","2":"credit","FirstName":"credit","3":"Giftcard","Address":"Giftcard","4":"Finance","City":"Finance"},{"0":"5","P_Id":"5","1":"zamor5","LastName":"zamor5","2":"credit","FirstName":"credit","3":"Giftcard","Address":"Giftcard","4":"Finance","City":"Finance"},{"0":"2","P_Id":"2","1":"zamor2","LastName":"zamor2","2":"credit","FirstName":"credit","3":"Giftcard","Address":"Giftcard","4":"Finance","City":"Finance"} 
]

注意到它有[{...}]而不是[...] ] 所以如果我更換我的aaData（硬編碼的，與上面這個）它讓我錯誤。我怎樣才能讓我的PHP代碼返回aaData中的東西。謝謝

來源

2012-07-30 Autolycus

替換第一個代碼塊的，你告訴是不是一個JSON字符串，也不是JavaScript對象符號的表示。它是一個擁有數組集合的數組。在您創建的數組中返回數組中的json_encode將輸出一個有效的JSON字符串。您需要相應地處理該字符串。使用'.getJSON（）'會得到你的那個對象（JSON解析和所有），然後你可以使用'$ .each'遍歷JSON字符串的集合。 – Ohgodwhy 2012-07-30 20:38:13

可能的重複[獲取正確的JSON格式]（http://stackoverflow.com/questions/11447582/getting-correct-json-format） – mario 2012-07-30 20:39:29

因爲你提供關聯數組列出。

php > $simple = array(1,2,3,4,5); 
php > $assoc = array('a'=> 1, 'b' => 2); 
php > echo json_encode($simple); 
[1,2,3,4,5] 
php > echo json_encode($assoc); 
{"a":1,"b":2}

嘗試與