SQL Server - LIKE [XXXX]

Question

我想只返回包含特定字段中的文本[XXXX]的值。 我的查詢返回有4位數字的值，因爲我假設SQL服務器將[XXXX]視爲任何具有4位數字的數字。

我有一個測試查詢下面的值列表來演示這個問題。

select X.VadDesc 
From (VALUES 
('Product AAAA Description'), 
('Product BBBB Description'), 
('Product [XXXX] Description'), 
('Product2 [XXXX] Description'), 
('Product 2 [AAAA] Description'), 
('Product X 1234 Description'), 
('Product X 1235 Description'), 
('Product X 1236 Description'), 
('Product X 1237 Description') 
) as X (VadDesc) 
Where X.VadDesc like '%[XXXX]%' 

我的查詢應該只返回：

Product [XXXX] Description 
Product2 [XXXX] Description 

但它返回：

Product [XXXX] Description 
Product2 [XXXX] Description 
Product X 1234 Description 
Product X 1235 Description 
Product X 1236 Description 
Product X 1237 Description 

我怎樣才能做到這一點？ 我不只是想尋找XXXX，因爲這可能是我不想返回的行。

Answer 1

select X.VadDesc 
From (VALUES 
('Product AAAA Description'), 
('Product BBBB Description'), 
('Product [XXXX] Description'), 
('Product2 [XXXX] Description'), 
('Product 2 [AAAA] Description'), 
('Product X 1234 Description'), 
('Product X 1235 Description'), 
('Product X 1236 Description'), 
('Product X 1237 Description') 
) as X (VadDesc) 
Where X.VadDesc like '%[[]XXXX]%' 

Answer 2

使用Escape character轉義[像這樣'%\[XXXX\]%' {escape '\'}。

查詢

select X.VadDesc 
From (VALUES 
('Product AAAA Description'), 
('Product BBBB Description'), 
('Product [XXXX] Description'), 
('Product2 [XXXX] Description'), 
('Product 2 [AAAA] Description'), 
('Product X 1234 Description'), 
('Product X 1235 Description'), 
('Product X 1236 Description'), 
('Product X 1237 Description') 
) as X (VadDesc) 
Where X.VadDesc like '%\[XXXX\]%' {escape '\'} 

SQL Fiddle