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我有一張收集客戶付款的表。我想從前3名客戶那裏得到每個客戶的付款。同一張表中的MySQL子查詢
下面的查詢獲得每個客戶每天每小時的總付款。下面
SELECT
hour(received) as hr,
login,
count(*) as total
FROM
payment
WHERE
received >= date("2011-02-24")
AND
received <date("2011-02-25")
AND
PAYMENT_BATCH_FILE_ID is null
GROUP BY
hr,
client_id
ORDER BY
hr,
total DESC
查詢獲得前3名的客戶端爲每一個客戶在一個小時內
SELECT
hour(received) as hr,
login,
count(*) as total
FROM
payment
WHERE
received >=date("2011-02-24")
AND
received < date("2011-02-25")
AND
PAYMENT_BATCH_FILE_ID is null
AND
hour(received)="3"
GROUP BY
hr,
client_id
ORDER BY
hr,
total DESC
LIMIT 3
如何將兩者結合起來的查詢獲得前3名的客戶,使每個小時支付?
謝謝。
有點失去了你在找什麼...你想要前3名的客戶嗎?或者每天每小時(72個結果)還是?還有點在「一小時內讓每位客戶獲得前三名客戶」中輸掉? – CarpeNoctumDC 2011-03-09 08:44:25
我想在一天中的每個小時內獲得3位客戶的信息 – muhdazmilug 2011-03-10 00:36:04