如何以隨機順序顯示內容？

Question

有了下面的代碼我顯示了從數據庫檢索的問題：

$qandaquery = "SELECT q.QuestionId, q.QuestionNo, q.QuestionContent 
        FROM Question q 
        WHERE SessionId = ? 
        GROUP BY q.QuestionId 
        ORDER BY q.QuestionId"; 

    $qandaqrystmt=$mysqli->prepare($qandaquery); 
    // You only need to call bind_param once 
    $qandaqrystmt->bind_param("i",$session); 
    // get result and assign variables (prefix with db) 
    $qandaqrystmt->execute(); 
    $qandaqrystmt->bind_result($qandaQuestionId,$qandaQuestionNo,$qandaQuestionContent); 

    $arrQuestionId = array(); 
    $arrQuestionNo = array(); 
    $arrQuestionContent = array(); 


    while ($qandaqrystmt->fetch()) { 
    $arrQuestionId[ $qandaQuestionId ] = $qandaQuestionId; 
    $arrQuestionNo[ $qandaQuestionId ] = $qandaQuestionNo; 
    $arrQuestionContent[ $qandaQuestionId ] = $qandaQuestionContent; 

    } 

    $qandaqrystmt->close(); 


foreach ($arrQuestionId as $key=>$question) { 

?> 

<div class='lt-container'> 
<p><strong>QUESTION <span id="quesnum"></span>:</strong></p> 
<p><?php echo htmlspecialchars($arrQuestionNo[$key]) . ": " . htmlspecialchars($arrQuestionContent[$key]); ?></p> 
</div> 


<?php 

} 

?> 

現在它說：QUESTION：

<p><strong>QUESTION # <?php echo $q; ?> :</strong></p> <?php $q++; ?>

我想要留在同一個地方

但它顯示問題的詳細信息：

<p><?php echo htmlspecialchars($arrQuestionNo[$key]) . ": " . htmlspecialchars($arrQuestionContent[$key]); ?></p> 

我希望它以RANDOM順序顯示問題。因此，舉例來說，如果我有3個問題如下：

QUESTION 1: 

1. What is 2+2? 

QUESTION 2: 

2. What is 3+3? 

QUESTION 3: 

3. What is 4+4? 

它可以顯示的順序作爲一個例子：

QUESTION 1: 

2. What is 3+3? 

QUESTION 2: 

3. What is 4+4? 

QUESTION 3: 

1. What is 2+2? 

Answer 1

代替ORDER BY q.QuestionId使用ORDER BY RAND()

Answer 2

的shuffle()函數隨機化數組中元素的順序。 Read more

例

<?php 
$my_array = array("a" => "Dog", "b" => "Cat", "c" => "Horse"); 

shuffle($my_array); 
print_r($my_array); 
?> 

rray ([0] => Cat [1] => Horse [2] => Dog) 

Answer 3

如何MySQL的rand（）函數例如

$qandaquery = "SELECT rand() as pos, q.QuestionId, q.QuestionNo, q.QuestionContent 
        FROM Question q 
        WHERE SessionId = ? 
        GROUP BY q.QuestionId 
        order by pos";