了和增加新的對象值到現有對象的值再次超過

Question

我需要讓結果出來作爲

{ username: 'Cloud', 
    species: 'sheep', 
    tagline: 'You can count on me!', 
    noises: ['baahhh', 'arrgg', 'chewchewchew'], 
    friends: [{username: 'Moo', species: 'cow'...}, {username: 'Zeny', species: 'llama'...}] 
} 

，但我的代碼目前打印編寫代碼首先爲新對象添加到現有對象，當我嘗試將另一個新對象添加到現有對象和console.log中時，它將替換最後添加的對象並僅添加新的對象值。

{ username: 'Cloud', 
    species: 'sheep', 
    tagline: 'You can count on me!', 
    noises: [ 'baahhh', 'arrgg', 'chewchewchew' ], 
    friends: 
    { username: 'Moo', 
    species: 'cow', 
    tagline: 'asdf', 
    noises: [ 'a', 'b', 'c' ], 
    friends: [] } } 
{ username: 'Cloud', 
    species: 'sheep', 
    tagline: 'You can count on me!', 
    noises: [ 'baahhh', 'arrgg', 'chewchewchew' ], 
    friends: 
    { username: 'Zeny', 
     species: 'llama', 
     tagline: 'qwerty', 
     noises: [ 'z', 'x', 'c' ], 
     friends: [] } } 

這是我的代碼到目前爲止。我只把animal2 = animal寫成它替換它，以便在添加另一個新的對象值時將它添加到該對象中，而不是原始對象。爲了完成這項工作，我需要在這裏做一個循環嗎？

function AnimalCreator(username, species, tagline, noises) { 
    var list = { 
    username: username, 
    species: species, 
    tagline: tagline, 
    noises: noises, 
    friends: [] 
    }; 

    return list; 

} 

function addFriend(animal, animal2) { 

    animal.friends = animal2; 
    animal2 = animal; 


} 

var sheep = AnimalCreator('Cloud', 'sheep', 'You can count on me!', ['baahhh', 'arrgg', 'chewchewchew']); 
var cow = new AnimalCreator('Moo', 'cow', 'asdf', ['a', 'b','c']); 
addFriend(sheep, cow); 
console.log(sheep); 
var llama = new AnimalCreator('Zeny', 'llama', 'qwerty', ['z', 'x', 'c']); 
addFriend(sheep,llama); 
console.log(sheep); 

我在做什麼錯？

Answer 1

您的問題看起來是在addFriend(animal, animal2)，您設置animal2 = animal。我認爲你想要做的是追加朋友，可以像

function addFriend(animal, animal2) { 
    var pastFriends=animal.friends; 
    pastFriends.push(animal2); 
    animal.friends = pastFriends; 
}