PHP：相交兩個數組並獲得這兩個值

Question

所以我有點卡在這裏，我可以用foreach循環來做，但我想找到一個更聰明的方式來做到這一點。

更新：有些事我在問題中已經錯過了。這些陣列可能隨機排列，長度不同，因此具有不同的鍵。以下示例已更新。

這裏是的情況下：

數組1

array (
    slug1 => England, 
    slug2 => France, 
    slug3 => Italy, 
    slug4 => Germany, 
) 

ARRAY2

array (
    slug2 => 215, 
    slug1 => 168, 
    slug4 => 55, 
    slug5 => 149, 
    slug3 => 40, 
    slug6 => 137, 
) 

欲相交這些陣列和建立新的一個，其具有以下要素：

array (
    168 => England, 
    215 => France, 
    40 => Italy, 
    55 => Germany, 
) 

注：元素雖然可以輕鬆實現，但沒有排序。

Answer 1

回答到原來的問題

可以使用array_combine它通過使用密鑰一個陣列，另一個用於其值

$array1 = array(
     "slug1" => "England", 
     "slug2" => "France", 
     "slug3" => "Italy", 
     "slug4" => "Germany"); 

$array2 = array(
     "slug1" => "168", 
     "slug2" => "215", 
     "slug3" => "40", 
     "slug4" => "55"); 

$final = array_combine($array2, $array1); 

echo "<pre>"; 
print_r($final); 

輸出

Array 
(
    [168] => England 
    [215] => France 
    [40] => Italy 
    [55] => Germany 
) 

See Live Demo

創建一個數組

答到更新的問題

Update: There was something that I've missed in the question. The arrays may come in random order and in different length thus having different keys. Examples below updated.

$array1 = array(
     "slug1" => "England", 
     "slug2" => "France", 
     "slug3" => "Italy", 
     "slug4" => "Germany"); 

$array2 = array (
     "slug2" => 215, 
     "slug1" => 168, 
     "slug4" => 55, 
     "slug5" => 149, 
     "slug3" => 40, 
     "slug6" => 137); 



$final = customCombine($array2, $array1); 

echo "<pre>"; 
print_r($final); 

輸出

Array 
(
    [215] => France 
    [168] => England 
    [55] => Germany 
    [40] => Italy 
) 

功能用於

function customCombine($keys, $arr) { 
    $t = array(); 
    foreach ($keys as $k => $val) { 
     isset($arr[$k]) and $t[$val] = $arr[$k]; 
    } 
    return $t; 
} 

Answer 2

使用array_combine()

<?php 
$a = array('green', 'red', 'yellow'); 
$b = array('avocado', 'apple', 'banana'); 
$c = array_combine($a, $b); 

print_r($c); 
?> 

http://in1.php.net/array-combine

Answer 3

巴巴的答案應該可以正常工作了你，但這裏同時處理陣列和/或不同尺寸之間不同的密鑰訂單一種有趣的方式。

// get values from $array2 in the order in which they appear in $array1 
// whereby the array keys are used to match them 
$keys = array_intersect_key($array2, $array1); 
// create a new array with the keys found in the previous step and 
// another array_intersect_key() to only select the matching items 
// from $array1 
array_combine($keys, array_intersect_key($array1, $keys)); 

它還確保array_combine()適用於相同大小的陣列; $array2的大小是輸出大小。

Answer 4

我發現對我來說最好的解決辦法：

http://eval.in/3578

<?php 

$array1 = array("slug1" => "England","slug2" => "France","slug3" => "Italy","slug4" => "Germany"); 
$array2 = array("slug1" => "168","slug2" => "215","slug3" => "40","slug4" => "55", "slug5" => "178"); 

ksort($array1); 
ksort($array2); 

$test1 = array_intersect_key($array1, $array2); 
$test2 = array_intersect_key($array2, $array1); 

$final = array_combine($test2, $test1); 
print_r($final); 
?> 

Answer 5

擴大Jack的答案，因爲它可能會結合他們正在建造中的順序排列，而不是訂單密鑰匹配：

Array 
(
    [215] => England 
    [168] => France 
    [55] => Italy 
    [40] => Germany 
) 

一些中間數據雜耍可以排序出來（和它無論哪個數組較短作品）：

$array1 = array(
    'slug1' => 'England', 
    'slug2' => 'France', 
    'slug3' => 'Italy', 
    'slug4' => 'Germany' 
); 

$array2 = array (
    'slug2' => 215, 
    'slug1' => 168, 
    'slug4' => 55, 
    'slug5' => 149, 
    'slug3' => 40, 
    'slug6' => 137 
); 

$keys = array_intersect_key($array2, $array1); 
ksort($keys); 
$intersect = array_intersect_key($array1, $keys); 
ksort($intersect); 
$final = array_combine($keys, $intersect); 

print_r($final); 

輸出

Array 
(
    [168] => England 
    [215] => France 
    [40] => Italy 
    [55] => Germany 
)