PHP上傳圖像信息編輯

Question

我有一個表單，允許我編輯數據庫中的數據。一旦表單提交，我需要 將圖像上傳到文件夾。這是一個編輯頁面，我設置的方式是從數據庫調用圖像名稱，並將圖像存儲在文件夾中。誰能幫我？

<?php 
// if there are any errors, display them 
if ($error != '') 
{ 
echo '<div style="padding:4px; border:1px solid red; color:red;">'.$error.'</div>'; 
} 
?> 

<form action="" method="post"> 
<input type="hidden" name="id" value="<?php echo $id; ?>"/> 
<div> 
<p><strong>ID:</strong> <?php echo $id; ?></p> 
<label> Job Name:</label><br><br> 
<input type="text" name="job_name" value="<?php echo $name; ?>"/><br/> 
<label></label><br><br> 
<label>Job Thumbnail:</label><br><br> 
<input id="upload" name="file" type="file" size="10"><br><br> 
<input id="filename" type="text" name="job_timg" placeholder="This Fills Automatcially" value="<?php echo $timg; ?>"/><br/> 
<label> Job Name:</label><br><br> 
<input type="submit" name="submit" value="Submit"> 
</div> 
</form> 
</body> 
</html> 
<?php 
} 

// connect to the database 
include('connect.php'); 

// check if the form has been submitted. If it has, process the form and save it to the database 
if (isset($_POST['submit'])) 
{ 
// $_FILES["file"]["error"] is HTTP File Upload variables $_FILES["file"] "file" is the name of input field you have in form tag. 

// confirm that the 'id' value is a valid integer before getting the form data 
if (is_numeric($_POST['id'])) 
{ 
// get form data, making sure it is valid 
$id = $_POST['id']; 
$name = mysql_real_escape_string(htmlspecialchars($_POST['job_name'])); 
$timg = mysql_real_escape_string(htmlspecialchars($_POST['job_timg'])); 

// check that name/image fields are both filled in 
if ($name == '' || $timg == '') 
{ 
// generate error message 
$error = 'ERROR: Please fill in all required fields!'; 

//error, display form 
renderForm($id, $name, $timg, $error); 
} 
else 
{ 
// save the data to the database 
mysql_query("UPDATE tbl_job SET job_name='$name', job_timg='$timg' WHERE job_id='$id'") 
or die(mysql_error()); 


// once saved, redirect back to the view page 
header("Location: gallery_edit.php"); 
} 
} 
else 
{ 
// if the 'id' isn't valid, display an error 
echo 'Error!'; 
} 
} 


else 
// if the form hasn't been submitted, get the data from the db and display the form 
{ 

// get the 'id' value from the URL (if it exists), making sure that it is valid (checing that it is numeric/larger than 0) 
if (isset($_GET['id']) && is_numeric($_GET['id']) && $_GET['id'] > 0) 
{ 
// query db 
$id = $_GET['id']; 
$result = mysql_query("SELECT * FROM tbl_job WHERE job_id=$id") 
or die(mysql_error()); 
$row = mysql_fetch_array($result); 

// check that the 'id' matches up with a row in the databse 
if($row) 
{ 

// get data from db 
$name = $row['job_name']; 
$timg = $row['job_timg']; 

// show form 
renderForm($id, $name, $timg, ''); 
} 
else 
// if no match, display result 
{ 
echo "No results!"; 
} 
} 
else 
// if the 'id' in the URL isn't valid, or if there is no 'id' value, display an error 
{ 
echo 'Error!'; 
} 


} 






?> 

Answer 1

在處理文件時，表單必須包含有效的enctype。

<form action="" method="post" enctype="multipart/form-data"> 

有關處理文件的更多信息，請訪問PHP.net以下頁面：

• http://php.net/manual/en/reserved.variables.files.php