如何在URL傳遞一個字符串值，在iPhone應用程序

NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.krsconnect.no/community/api.html?method=bareListEventsByCategory&appid=620&category-selected=350&counties-selected=Vest-Agder,Aust-Agder 

NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.krsconnect.no/community/api.html?method=bareListEventsByCategory&appid=620&category-selected=catId&counties-selected=Vest-Agder,Aust-Agder"]]; 

NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; 
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding]; 
NSDictionary *object = [parser objectWithString:json_string error:nil]; 
NSArray *results = [parser objectWithString:json_string error:nil];

我有這個網址我想，類別選擇= 350應變量獲得價值如何做到這一點我做的，但沒有得到結果，如果我給VAR名稱，而不是350如何在URL傳遞一個字符串值，在iPhone應用程序

來源

2011-08-17 ali

你可以試試這個：

NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://www.businessfactors.de/bfcms/images/stories/videos/%@.mp4",strtext]]; 
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:url]];

來源

2011-08-17 07:04:22

使用NSString stringWithFormat與伊娃格式化的網址：

NSString *catId = @"350"; 
NSString *url = [NSString stringWithFormat:@"http://www.krsconnect.no/community/api.html?method=bareListEventsByCategory&appid=620&category-selected=%@&counties-selected=Vest-Agder,Aust-Agder", catId]; 
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:url]];

來源

2011-08-17 04:48:56

我可以把所有的URL中的NSString – ali

- [NSCFNumber長]：無法識別的選擇發送到實例0x9307c60 這是給異常，當我使用這個 – ali

如果你的參數是一個整數，你應該使用％d參數而不是％@。請參閱[Apple格式指南]（http://developer.apple.com/library/mac/#documentation/Cocoa/Conceptual/Strings/Articles/formatSpecifiers.html#//apple_ref/doc/uid/TP40004265-SW1） –

發送使用stringByURLEncode，stringByURLDecode

- (NSString *)stringByURLDecode { 

     NSMutableString *tempStr = [NSMutableString stringWithString:self]; 
     [tempStr replaceOccurrencesOfString:@"+" withString:@" " options:NSCaseInsensitiveSearch range:NSMakeRange(0, [tempStr length])]; 

     return [[NSString stringWithFormat:@"%@",tempStr] stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; 

    } 

    - (NSString *)stringByURLEncode { 

     NSMutableString *tempStr = [NSMutableString stringWithString:self]; 
     [tempStr replaceOccurrencesOfString:@" " withString:@"+" options:NSCaseInsensitiveSearch range:NSMakeRange(0, [tempStr length])]; 


     return [[NSString stringWithFormat:@"%@",tempStr] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; 

    }

來源

2012-04-07 12:29:36 dayitv89

如何在URL傳遞一個字符串值，在iPhone應用程序

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