我正在關注http://www.raywenderlich.com/13511/how-to-create-an-app-like-instagram-with-a-web-service-backend-part-12#comments教程。我開了一個XAMPP服務器當我打開http://localhost/iReporter
因爲iReporter是文件夾的名稱和錯誤是解析錯誤:語法錯誤,意外的T_STRING與XAMPP
Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/iReporter/lib.php on line 5
這裏是lib.php代碼:
<?
//setup db connection
$link = mysqli_connect("localhost","root","")
mysqli_select_db($link, "iReport");
//executes a given sql query with the params and returns an array as result function
query() {
global $link;
$debug = false;
//get the sql query
$args = func_get_args();
$sql = array_shift($args);
//secure the input
for ($i=0;$i<count($args);$i++) {
$args[$i] = urldecode($args[$i]);
$args[$i] = mysqli_real_escape_string($link, $args[$i]);
}
//build the final query
$sql = vsprintf($sql, $args);
if ($debug) print $sql;
//execute and fetch the results
$result = mysqli_query($link, $sql);
if (mysqli_errno($link)==0 && $result) {
$rows = array();
if ($result!==true)
while ($d = mysqli_fetch_assoc($result)) {
array_push($rows,$d);
}
//return json
return array('result'=>$rows);
} else {
//error
return array('error'=>'Database error');
}
}
//loads up the source image, resizes it and saves with -thumb in the file name function thumb($srcFile, $sideInPx) {
$image = imagecreatefromjpeg($srcFile);
$width = imagesx($image);
$height = imagesy($image);
$thumb = imagecreatetruecolor($sideInPx, $sideInPx);
imagecopyresized($thumb,$image,0,0,0,0,$sideInPx,$sideInPx,$width,$height);
imagejpeg($thumb, str_replace(".jpg","-thumb.jpg",$srcFile), 85);
imagedestroy($thumb);
imagedestroy($image);
}
?>
什麼是我的問題嗎?請幫忙!
- 編輯 -
現在它說,有一個錯誤與線35時,我改變 $link = mysqli_connect("localhost","root","")
到 $link = mysqli_connect("localhost","root","");
!