2013-07-09 109 views
0

我正在關注http://www.raywenderlich.com/13511/how-to-create-an-app-like-instagram-with-a-web-service-backend-part-12#comments教程。我開了一個XAMPP服務器當我打開http://localhost/iReporter因爲iReporter是文件夾的名稱和錯誤是解析錯誤:語法錯誤,意外的T_STRING與XAMPP

Parse error: syntax error, unexpected T_STRING in /Applications/XAMPP/xamppfiles/htdocs/iReporter/lib.php on line 5

這裏是lib.php代碼:

<?

//setup db connection

$link = mysqli_connect("localhost","root","")

mysqli_select_db($link, "iReport");

//executes a given sql query with the params and returns an array as result function
query() {

global $link;

$debug = false;

//get the sql query 
$args = func_get_args(); 
$sql = array_shift($args); 
//secure the input 
for ($i=0;$i<count($args);$i++) { 
    $args[$i] = urldecode($args[$i]); 
    $args[$i] = mysqli_real_escape_string($link, $args[$i]); 
} 

//build the final query 
$sql = vsprintf($sql, $args); 

if ($debug) print $sql; 

//execute and fetch the results 
$result = mysqli_query($link, $sql); 
if (mysqli_errno($link)==0 && $result) { 

    $rows = array(); 
    if ($result!==true) 
    while ($d = mysqli_fetch_assoc($result)) { 
     array_push($rows,$d); 
    } 

    //return json 
    return array('result'=>$rows); 

} else { 

    //error 
    return array('error'=>'Database error'); 
} 

}

//loads up the source image, resizes it and saves with -thumb in the file name function thumb($srcFile, $sideInPx) {

$image = imagecreatefromjpeg($srcFile);

$width = imagesx($image);

$height = imagesy($image);

$thumb = imagecreatetruecolor($sideInPx, $sideInPx);

imagecopyresized($thumb,$image,0,0,0,0,$sideInPx,$sideInPx,$width,$height);

imagejpeg($thumb, str_replace(".jpg","-thumb.jpg",$srcFile), 85);

imagedestroy($thumb); imagedestroy($image); }

?>

什麼是我的問題嗎?請幫忙!

- 編輯 -

現在它說,有一個錯誤與線35時,我改變 $link = mysqli_connect("localhost","root","")$link = mysqli_connect("localhost","root","");

回答

0

有一個mising「;」在線路

$link = mysqli_connect("localhost","root","") 

,並且必須是

$link = mysqli_connect("localhost","root",""); 
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