gnuplot的閱讀Unix時間戳

Question

我有數據的文件格式如下：

1351649601.045 421 2945 
1351649601.684 1036 28591 
1351649603.310 128 1620 
1351649603.413 93 0 
1351649603.375 132 1762 
1351649603.318 218 1761 
1351649603.434 412 176 
1351649603.441 520 5780 
1351649603.480 565 11070 
1351649603.556 644 11535 


gnuplot> set term png 
Terminal type set to 'png' 
gnuplot> set output "output.png" 
gnuplot> plot "data.txt" using 1:2 with lines 

但是日期不正確的想法gnuplot..any讀？

解決：

set term png xffffff 
set output "output.png" 
set size 17,17 
set title "HTTP payload size and response time" 
set style data fsteps 
set xlabel "Date" 
set timefmt "%s" 
set format x "%m/%d/%Y %H:%M:%S" 
set xdata time 
set ylabel "Payload/Response time" 
set grid 
set key left 
plot 'response' usi 1:2 with linespoints 

Answer 1

對不起，似乎無法刪除。要建議：

set xdata time 
set timefmt "%s" 
set format x "%m/%d/%Y %H:%M:%S" 
plot "file.txt" using 1:2 with linespoints 

但它截斷部分，並從線下降分。