4
我在三個表上使用內部連接,並且顯示結果表。我爲此使用了Xml。Javascript格式異常
<SQLInformation>
<Table>tblechecklistprogramworkpackagexref prwpxref</Table>
<TableJoins>
INNER JOIN tblechecklistprogram pr ON pr.ixProgram=prwpxref.ixProgram
INNER JOIN tblechecklistworkpackage wp ON wp.ixWorkPackage=prwpxref.ixWorkPackage
INNER JOIN tblechecklistworkpackageactivityxref wpaxref ON wpaxref.ixWorkPackage=wp.ixWorkPackage
INNER JOIN tblechecklistactivity act ON act.ixActivity=wpaxref.ixActivity
</TableJoins>
<WhereClause>
</WhereClause>
<GroupBy>
</GroupBy>
<OrderBy></OrderBy>
<HeaderInformation></HeaderInformation>
<FooterInformation></FooterInformation>
</SQLInformation>
<Columns>
<Column>
<Id>ProgramName</Id>
<Title>Program Name</Title>
<Table>pr</Table>
<Field>sName</Field>
<Alias>sName</Alias>
<Sortable>true</Sortable>
<GroupSort>true</GroupSort>
<ColumnWidth>100</ColumnWidth>
<JavascriptFormatter>
<![CDATA[
DesignDataFileFormatter = function(span,row,columns,data,item)
{
$(span).createAppend('a', {href: '../EcheckList/TemplateUsage.aspx?IxTemplate=' + 2, title: 'Go to Corresponding Schedule Item.', innerHTML:sName });
return true;
}
]]>
</JavascriptFormatter>
<Display>true</Display>
<Filter type="Database">
<FilterContainer name="Program" DisplayMember="sName" ValueMember="ixProgram" UseHavingClause="false" >
<FilterQuery>SELECT sName,ixProgram FROM tblechecklistprogram</FilterQuery>
</FilterContainer>
</Filter>
</Column>
我想創建一個使用輸出表的列值之一的超鏈接。每當我點擊鏈接時,它都會給出格式異常。
現在iam能夠重定向到頁面。但是如果我想將值傳遞給頁面,我該怎麼做呢?我想清除關於href中應該給出的值。爲什麼它給虛擬路徑提供錯誤? –