如何在最後一次輸出結果，而不是在使用for循環時逐一輸出結果？

Question

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 

int main (void) { 
    int n, i, input_cases,x; 
    scanf("%d", &input_cases); 
    float *results = malloc(input_cases*sizeof(float)); 

    for (x=0; x<input_cases; x++){ 
    float num[100], sum[2] = {0.0}, average[2] = {0.0}; 
    printf("Enter the total amount of numbers: "); 
    if (scanf("%d", &n) != 1) { /* validates input */ 
     fprintf (stderr, "error: invalid input.\n"); 
     return 1; 
    } 
    for (i = 0; i < n; i++) { 
     if (scanf("%f", &num[i]) != 1) { /* validate input */ 
      fprintf (stderr, "error: invalid input.\n"); 
      return 1; 
     } 
    } 
    /* sum/average 1st-half */ 
    for (i = 0; i < n/2; ++i){ 
     sum[0] += num[i]; 
     average[0] = sum[0] * 2/n; 
    } 
    /* sum/average 2nd-half */ 
    for (i = n/2; i < n; ++i){ 
     sum[1] += num[i]; 
     average[1] = sum[1] * 2/n; 
    } 
    if (average[0]>average[1]){ 
      results[x]=average[0]; 
      printf("%.6f\n", average[0]); 
    } 
    else{ 
      results[x]=average[1]; 
      printf("%.6f\n", average[1]);} 
    } 
    for (x=0; x<input_cases; x++){ 
     printf("%.6f\n", results[x]); 
     free(results); 
    } 
    return 0; 
} 

這是我的代碼呢：

Input: 
2 
Enter the total amount of numbers: 10 
10 
8 
9 
15 
12 
2 
3 
8 
7 
11 
10.800000(This is the output) 
Enter the total amount of numbers: 4 
3 
3 
2 
1 
3.000000(This is the output) 
10.800000(My output when i dynamically allocate an array to display everything at the end) 
0.000000(My output when i dynamically allocate an array to display everything at the end) 

這是我真正想要的樣子：

Input: 
2 
Enter the total amount of numbers: 10 
10 
8 
9 
15 
12 
2 
3 
8 
7 
11 
Enter the total amount of numbers: 4 
3 
3 
2 
1 

Output: 
10.800000 
3.000000 

我怎麼能採取什麼樣的，我從我的計算了，並讓他們所有輸出都在最後，而不是在每次計算結束時單獨輸出每個輸出？

Answer 1

您應該free和array打印完所有的值後。但是你做錯了，那就是你在free那array打印第一個值後。我想你明白了。

#include <stdio.h> 
#include <stdlib.h> 
#include <string.h> 

int main (void) 
{ 
    int n, i, input_cases,x; 
    scanf("%d", &input_cases); 
    float *results = malloc(input_cases*sizeof(float)); 
    int increment=0; 

    for (x=0; x<input_cases; x++) 
    { 
     float num[100], sum[2] = {0.0}, average[2] = {0.0}; 
     printf("Enter the total amount of numbers: "); 
     if (scanf("%d", &n) != 1) /* validates input */ 
     { 
      fprintf (stderr, "error: invalid input.\n"); 
      return 1; 
     } 
     for (i = 0; i < n; i++) 
     { 
      if (scanf("%f", &num[i]) != 1) /* validate input */ 
      { 
       fprintf (stderr, "error: invalid input.\n"); 
       return 1; 
      } 
     } 
     /* sum/average 1st-half */ 
     for (i = 0; i < n/2; ++i) 
     { 
      sum[0] += num[i]; 
      average[0] = sum[0] * 2/n; 
     } 
     /* sum/average 2nd-half */ 
     for (i = n/2; i < n; ++i) 
     { 
      sum[1] += num[i]; 
      average[1] = sum[1] * 2/n; 
     } 
     if (average[0]>average[1]) 
     { 
      results[increment++]=average[0]; 
      printf("%.6f\n", average[0]); 
     } 
     else 
     { 
      results[increment++]=average[1]; 
      printf("%.6f\n", average[1]); 
     } 
    } 
    for (x=0; x<input_cases; x++) 
    { 
     printf("%.6f\n", results[x]); 
     //free(results); 
    } 

    free(results); 
    return 0; 
}