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我想獲取具有mhId =「AAA」的用戶的id和名稱(mhId是表User_MonHoc中的一列,在User_MonHoc中,mhid + user_id是主鍵)。如何使用WHERE子句選擇多個表
表用戶:
<hibernate-mapping>
<class name="entites.User" table="user" catalog="bthibernate" optimistic-lock="version">
<id name="username" type="string">
<column name="username" length="100" />
<generator class="assigned" />
</id>
<property name="password" type="string">
<column name="password" length="100" not-null="true" />
</property>
<property name="note" type="byte">
<column name="note" not-null="true" />
</property>
<property name="name" type="string">
<column name="name" length="100" not-null="true" />
</property>
<set name="userMonhocs" table="user_monhoc" inverse="true" lazy="true" fetch="select">
<key>
<column name="user_id" length="100" not-null="true" />
</key>
<one-to-many class="entites.UserMonhoc" />
</set>
</class>
表User_MonHoc
<hibernate-mapping>
<class name="entites.UserMonhoc" table="user_monhoc" catalog="bthibernate" optimistic-lock="version">
<composite-id name="id" class="entites.UserMonhocId">
<key-property name="userId" type="string">
<column name="user_id" length="100" />
</key-property>
<key-property name="mhId" type="string">
<column name="mh_id" length="100" />
</key-property>
</composite-id>
<many-to-one name="monhoc" class="entites.Monhoc" update="false" insert="false" fetch="select">
<column name="mh_id" length="100" not-null="true" />
</many-to-one>
<many-to-one name="user" class="entites.User" update="false" insert="false" fetch="select">
<column name="user_id" length="100" not-null="true" />
</many-to-one>
<property name="thoigianDk" type="timestamp">
<column name="thoigian_dk" length="19" not-null="true" />
</property>
</class>
我想ID和用戶名,誰擁有mhId = 「AAA」(mhId是表User_MH中的一列)。 謝謝!