刪除字符串中的項目

Question

如何刪除字符串中的其他內容並返回由其他字符串組成的列表？這是我寫的。提前致謝！！！

def get_poem_lines(poem): 
r""" (str) -> list of str 

Return the non-blank, non-empty lines of poem, with whitespace removed 
from the beginning and end of each line. 

>>> get_poem_lines('The first line leads off,\n\n\n' 
... + 'With a gap before the next.\nThen the poem ends.\n') 
['The first line leads off,', 'With a gap before the next.', 'Then the poem ends.'] 
""" 

list=[] 
for line in poem: 
    if line == '\n' and line == '+': 
     poem.remove(line) 
s = poem.remove(line) 
for a in s: 
    list.append(a) 
return list 

Answer 1

split和strip可能是你需要的東西：

s = 'The first line leads off,\n\n\n  With a gap before the next.\nThen the poem ends.\n' 

print([line.strip() for line in s.split("\n") if line]) 
['The first line leads off,', 'With a gap before the next.', 'Then the poem ends.'] 

不知道其中+適合的，因爲它是，如果它是某種要麼條參與或者str.replace它，也避免使用list作爲變量名，它會影響Python的list。

最後字符串沒有remove方法，你可以.replace但由於字符串是不可變的你需要的poem重新分配的返回值取代IE poem = poem.replace("+","")

Answer 2

你可以閱讀所有非空行像這樣：

list_m = [line if line not in ["\n","\r\n"] for line in file]; 

不看你的輸入樣本，我假設你只是想要你的空白處被刪除。在這種情況下，

for x in range(0, len(list_m)): 
    list_m[x] = list_m[x].replace("[ ](?=\n)", "");