我試圖用DECIMAL(5,2)數據類型更新列。但是,SQL Server似乎正在四捨五入,而不是存儲小數位。SQL Server更新不更新小數
例如,其中一個值爲1.53,並且其在表中存儲爲1.00。
這裏的查詢
DECLARE @MaxLike DECIMAL (5,2), @MaxComment DECIMAL (5,2), @MaxFavourite DECIMAL (5,2)
SET @MaxLike = 1.0*100/(SELECT MAX(z.MaxLike) FROM (SELECT(COUNT(COALESCE(Liked,0))) AS MaxLike FROM Design_LikeRating GROUP BY DesignID) z)
SET @MaxComment = 1.0*100/(SELECT MAX(z.MaxComment) FROM (SELECT(COUNT(COALESCE(CommentID,0))) AS MaxComment FROM Comment_CommentDetail WHERE IsDeleted = 0 GROUP BY OverallParentGUID) z)
SET @MaxFavourite = 1.0*100/(SELECT MAX(z.MaxFavourite) FROM (SELECT (COUNT(COALESCE(DesignID,0))) AS MaxFavourite FROM Design_Favourite GROUP BY DesignID) z)
-- VoteCount and Rate
DECLARE @table1 TABLE (DesignID INT PRIMARY KEY, Rate DECIMAL(5,2))
INSERT INTO @table1
SELECT DesignID, CAST (Rate AS DECIMAL(5,2)) AS Rate
FROM
(
SELECT DesignID, COUNT(COALESCE(Liked,0.0)) AS Rate
FROM Design_LikeRating WITH (NOLOCK)
GROUP BY DesignID
) z
-- FavCount
DECLARE @table2 TABLE (DesignID INT PRIMARY KEY, FavCount DECIMAL(5,2))
INSERT INTO @table2
SELECT DesignID, CAST (FavCount AS DECIMAL (5,2)) AS FavCount
FROM
(
SELECT DesignID, COUNT(COALESCE(DesignID,0.0)) AS FavCount
FROM Design_Favourite WITH (NOLOCK)
GROUP BY DesignID
) x
-- CommentCount
DECLARE @table3 TABLE (DesignGUID UNIQUEIDENTIFIER PRIMARY KEY, CommentCount DECIMAL(5,2))
INSERT INTO @table3
SELECT OverallParentGUID, CAST (CommentCount AS DECIMAL(5,2)) AS CommentCount
FROM
(
SELECT OverallParentGUID, COUNT(DISTINCT COALESCE(x.DesignID,0.0)) AS CommentCount
FROM Comment_CommentDetail z WITH (NOLOCK)
INNER JOIN Design_DesignDetail x WITH (NOLOCK) ON x.DesignGUID = z.OverallParentGUID
WHERE z.IsDeleted = 0 AND x.UserIDInt != z.UserIDInt
GROUP BY OverallParentGUID
) y
;
WITH CTE AS
(
SELECT (COALESCE((1.0 * z.Rate*@MaxLike),0.0) + COALESCE((1.0 * y.FavCount*@MaxFavourite),0.0) + COALESCE((1.0 * x.CommentCount*@MaxFavourite),0.0)) AS PopularityScore, a.DesignID
FROM Design_DesignDetail a
LEFT JOIN @table1 AS z ON z.DesignID = a.DesignID
LEFT JOIN @table2 AS y ON y.DesignID = a.DesignID
LEFT JOIN @table3 AS x ON x.DesignGUID = a.DesignGUID
WHERE DesignID > 300000 and DesignID = 444409
)
UPDATE Design_DesignDetail
SET PopularityScore = z.PopularityScore
FROM Design_DesignDetail a
INNER JOIN CTE z on z.DesignID = a.DesignID
UPDATE 我會停下巧言令色並張貼在這裏整個查詢。正如你所看到的,它得到了所有人的答案,但它仍然沒有工作!
請看我的更新 – gbn 2010-11-12 20:58:58