如何使一個數字，一個字符串中的關鍵，而拆分一個字符串值

Question

def check(string): 
    list2 = {} 

    for eachstring in string: #eachstring in the input string 

      if eachstring.isdigit(): #evaluates if the string is a number 

       list2[int(eachstring)] = string 

    return list2 #This outputs [2: ""h2llo I3", 3: ""h2llo I3"] 
        # I want it so it outputs [2: "h2llo", 3: "I3"]     


print (check("h2llo I3")) 

Answer 1

這是另一種方式，可能不是最好的。

def check(string): 
string = string.split() 
list2 = {} 
for eachword in string: #each word in the input string 
    for eachstring in eachword: 
     if eachstring.isdigit(): #evaluates if the string is a number 
      list2[int(eachstring)] = eachword 

return list2 # outputs [2: "h2llo", 3: "I3"]     


print (check("h2llo I3")) 

Answer 2

試試這個，拆你的字符串和迭代每個字符：

def check(string): 
    return {e:i for i in string.split() for e in i if e.isdigit()} 


print (check("h2llo I3")) 

輸出：

{'3': 'I3', '2': 'h2llo'} 

Answer 3

你的代碼中的問題是。您將分配整個字符串，或將單詞（eachstring）分配爲字典中的值。

嘗試list2[int(eachstring)] = eachstring

Answer 4

def check(string): 
    list2 = {} 
    nu = string 
    for char in string: #use char present the one char 

     if char.isdigit(): 
      nu = nu.split(' ') 
      list2[int(char)] = nu[0] 
      del nu[0] 
      nu = ' '.join(nu) 

    return list2 

，這將是right.your list2[int(eachstring)] = string將會把所有的整個輸入是你的價值。