0
我想要一個實例,用戶可以使用input()
語句訪問該實例。 這裏是我的三個實例python - 將用戶輸入設置爲實例
water1 = waterType("squirtle", 50)
grass1 = grassType("bulbasaur", 50)
fire1 = fireType("charmander", 50)
這裏就是我的意思
class waterType(Pokemon):
"""creates a water pokemon"""
pokemon_type = "water"
damage = 10
def __init__(self, name, hp):
self.name = name
self.hp = hp
def growl(self):
print("Splish Splosh")
def attack(self):
enemy = input("Who do you want to attack?") <--- over here, I would enter "fire1"
"""attribute error occurs here"""
if (enemy.pokemon_type == "fire"):
global damage
water1.damage = water1.damage*2
enemy.hp = enemy.hp - water1.damage
return enemy.hp
print ("It was super effective!")
print (enemy.hp)
如果我把所有的「敵人」,並以「FIRE1」取代它,一切都完美的作品。但是,那麼我需要手動輸入每個單一的火型實例。
如果無法將實例分配給輸入,是否有任何方法可以修復我的代碼?
謝謝,這正是我想要的! – Coolunized5
沒問題,祝你好運! – Windmill