Joomla 2.5變量全局組件範圍

Question

我開發自定義Joomla 2.5後端組件。我想知道在我的組件範圍內進行變量全局的最佳實踐。我應該在組件主控制器中放置聲明嗎？

class MyController extends JController 
{  

     /** 
     * 
     * @var object External database object 
     */ 
     public $dbExternal; 


     function __construct($config = array()) 
     { 

      $this->dbExternal = $this->_getDbInstance();    
      JTable::setDbo($this->dbExternal); 

      parent::__construct($config); 

     } 

     /** 
    * Display task 
    * 
    * @return void 
    */ 
    function display($cachable = false, $urlparams = false) 
    { 
     // set default view if not set 
     JRequest::setVar('view', JRequest::getCmd('view', 'My')); 

     // call parent behavior 
     parent::display($cachable); 

     // Set the submenu 
     MyHelper::addSubmenu('messages'); 
    } 

     /** 
     * Getting instance of the database 
     * 
     * @return instance $dbExternal Return db instance on success 
     */ 
     private function _getDbInstance() 
     { 
      $params = $this->_getDbParams(); 

      $dbExternal = JDatabase::getInstance($params); 

      if ($dbExternal->getErrorNum() > 0) 
      {     
       JError::raiseWarning(500, 'JDatabase::getInstance: '. 
       $dbExternal->getErrorMsg()); 
       $this->isError = true; 
      } 

      return $dbExternal; 
     } 

     /** 
     * Getting external db parameters 
     * 
     * @return array $dbParamsArr Return db params on success 
     */ 
     private function _getDbParams() 
     { 
      $dbParamsArr    = array(); 

      $params = JComponentHelper::getParams('com_my'); 

      $dbParamsArr['host']  = $params->get('db_host'); 
      $dbParamsArr['user']  = $params->get('db_user'); 
      $dbParamsArr['password'] = $params->get('db_password'); 
      $dbParamsArr['database'] = $params->get('db_database'); 
      $dbParamsArr['driver'] = $params->get('db_driver'); 

      return $dbParamsArr; 
     } 
} 

所以我想在任何其他組件控制器或模型中達到$ dbExternal。有任何想法嗎？

Answer 1

要從另一個組件訪問$dbExternal變量，您需要先實例化一個MyController對象。在您有MyController的實例之前，$dbExternal變量不存在。

$myController = new MyController(); 
$dbExternal = $myController->$dbExternal;