在Java中將不可打印的字符打印爲完整版

Question

我有一個需要轉換爲ASCII並打印的十六進制字符串。在調試時，我可以看到正確的值，但是當我嘗試打印ASCII時，它會忽略它並轉到下一個。有沒有辦法以點（。）替換所有不可打印的字符。這裏是我的代碼片段：

import javax.xml.bind.DatatypeConverter; 
byte[] out = toByteArray("0000005401F40000D9E3C60500000000002000000000000000D7C8F10000000000000000000000004040404040404040D9E3C600E9C7C9F0F0F0F1F1E5D9C1D1C1D54040F0F0F14BF0F0F14BF0F0F14BF0F0F100"); // Input Hex String 
System.out.println("ASCII: " + out); // Prints [B@15db9742 
String hex = toHexString(out); 
System.out.println("Hex: " + hex); // Prints the hex - 00000054 exactly 

public static String toHexString(byte[] array) { 
    return DatatypeConverter.printHexBinary(array); 
} 

public static byte[] toByteArray(String s) { 
    return DatatypeConverter.parseHexBinary(s); 
} 

Answer 1

import java.util.Arrays; 

import javax.xml.bind.DatatypeConverter; 
public class Main { 

    public Main() { 
     // TODO Auto-generated constructor stub 
    } 

    public static void main(String[] args) { 

     byte[] out = toByteArray("0000005401F40000D9E3C60500000000002000000000000000D7C8F10000000000000000000000004040404040404040D9E3C600E9C7C9F0F0F0F1F1E5D9C1D1C1D54040F0F0F14BF0F0F14BF0F0F14BF0F0F100"); // Input Hex String 
     System.out.println("ASCII: " + Arrays.toString(out)); 
     String hex = toHexString(out); 
     System.out.println("Hex: " + hex); // Prints the hex - 00000054 exactly 


    } 
    public static String toHexString(byte[] array) { 
     return DatatypeConverter.printHexBinary(array); 
    } 

    public static byte[] toByteArray(String s) { 
     return DatatypeConverter.parseHexBinary(s); 
    } 

} 

輸出更換的

例子：

//non-ASCII 
String yourstring = Arrays.toString(out).replaceAll("[^\\x00-\\x7F]", "."); 


    //non-printable characters 
String yourstring = Arrays.toString(out).replaceAll("\\p{C}", ".");