我想此PHP MySQL查詢Laravel查詢生成器:Laravel查詢生成器 - 其中(1 = 1)得到錯誤
$sql = "SELECT employee_name, employee_salary, employee_position, employee_city, employee_extension, DATE_FORMAT(employee_joining_date, '%Y-%m-%d') as employee_joining_date, employee_age ";
$sql .= " FROM employee WHERE 1=1";
if (!empty($EmployeeNameSeach)) {
$sql .=" AND employee_name LIKE '".$EmployeeNameSeach."%' ";
}
if (!empty($SalarySeach)) {
$sql .= " AND employee_salary LIKE '".$SalarySeach."%' ";
}
if (!empty($PositionNameSeach)) {
$sql .= " AND employee_position LIKE '".$PositionNameSeach."%' ";
}
if (!empty($CitySeach)) {
$sql .= " AND employee_city LIKE '".$CitySeach."%' ";
}
if (!empty($ExtensionSeach)) {
$sql .= " AND employee_extension LIKE '".$ExtensionSeach."%' ";
}
if (!empty($JoiningDataSeach)) {
$sql .= " AND employee_joining_date LIKE '".$JoiningDataSeach."%' ";
}
if (!empty($AgeSeach)) {
$sql .= " AND employee_age LIKE '".$AgeSeach."%' ";
}
什麼我做的是 -
$baseQuery = DB::table('employee')->select('employee_name', 'employee_salary', 'employee_position', 'employee_city', 'employee_extension',"employee_joining_date", 'employee_age', 'employee_id');
//->select('name as user_name', 'email')
//Applying Filters
$query = $baseQuery->where(1, '=', 1);
if(!empty($EmployeeNameSeach))
$query = $query->orWhere('employee_name', 'LIKE', '%'.$EmployeeNameSeach.'%');
if(!empty($SalarySeach))
$query = $query->orWhere('employee_name', 'LIKE', '%'.$SalarySeach.'%');
if(!empty($PositionNameSeach))
$query = $query->orWhere('employee_name', 'LIKE', '%'.$PositionNameSeach.'%');
if(!empty($CitySeach))
$query = $query->orWhere('employee_name', 'LIKE', '%'.$CitySeach.'%');
if(!empty($ExtensionSeach))
$query = $query->orWhere('employee_name', 'LIKE', '%'.$ExtensionSeach.'%');
if(!empty($JoiningDataSeach))
$query = $query->orWhere('employee_name', 'LIKE', '%'.$JoiningDataSeach.'%');
if(!empty($AgeSeach))
$query = $query->orWhere('employee_name', 'LIKE', '%'.$AgeSeach.'%');
//Ordering and Limiting Current data
$query = $query->orderBy($columns[$column_index_for_ordering], $column_ordering_direction)
->skip($start_data_index)->take($per_page_content_number);
$data = $query->get();
所以我得到錯誤 -
$query = $baseQuery->where(1, '=', 1);
任何人都可以幫助我嗎? 謝謝。
我相信他不需要使用'orWhere'以及它是'or'語句。問題在查詢中具有所有'和'。 – user3158900
@ user3158900 - 無論哪種情況,都不需要「WHERE 1 = 1」。 –
'where'條件應該使用'$$ filter'以及:)。 – Bogdan